1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nimfa-mama [501]
1 year ago
15

What can the presence of suffixes such as -ite,-ate,or -de in a chemical name indicate?

Chemistry
1 answer:
laila [671]1 year ago
3 0

Answer: Most polyatomic ions are -ate, related ions that have 1 fewer oxygen atom are -ite (must have at least 1 oxygen tho) and nonmetals are ide.

Explanation:

You might be interested in
What mass of melamine, c3n3(nh2)3, will be obtained from 113.0 kg of urea, co(nh2)2, if the yield of the overall reaction is 73.
creativ13 [48]

The balanced equation for the reaction is:

6 HNCO(l) → C3N3(NH2)3(l) + 3 CO2(g)

Convert amount of urea from kg to moles

Molar Mass of urea = 60.06 g/mol so, 113 kg urea contains

113 kg / 60.06 = 1.88 mol urea

From balanced equation 6 moles of urea yields only 1 melamine, so divide the moles of urea by 6. 

1.88 / 6 = 0.313 kmol melamine

Now multiply 0.313 with molar mass of melamine that is 126 g/mol

126 x 0.313 = 39.438 kg

Yield of overall reaction is 73% so multiply 39.438 with 0.73

<span>39.438 x 0.73 = 28.799 kg is the answer</span>

6 0
3 years ago
If sodium (Na) bonds with chlorine (Cl), which statement is true?
Ray Of Light [21]

Answer:

First option is the correct answer

Explanation:

An electron is transferred from sodium to chlorine and an ionic bond is formed.

7 0
3 years ago
Read 2 more answers
Using the Lewis dot Symbol Illustrate how the atoms are bonded in each of the following ionic compounds; thanks
Gre4nikov [31]
I’m not really sure but i think it’s 2.
6 0
3 years ago
The half-life of bismuth-210, 210bi, is 5 days. (a) if a sample has a mass of 184 mg, find the amount remaining after 15 days.
ASHA 777 [7]

Answer:- 23.0 mg

Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:

lnN=-kt+lnN_0

where, N_0 is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.

From given information, Original amount, N_0 of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days

Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:

k=\frac{0.693}{t_1_/_2}

where, t_1_/_2 is the symbol for half life. let's plug in the value of half like to calculate k:

k=\frac{0.693}{5days}

k=0.1386day^-^1

Let's plug in the values in the first order kinetics equation and solve it for N:

lnN=-0.1386day^-^1(15days)+ln184mg

lnN=-2.079+5.215

lnN = 3.136

N=e^3^.^1^3^6

N = 23.0 mg

So, 23.0 mg of Bi-210 would be remaining after 15 days.

3 0
4 years ago
When the following oxidation-reduction occurs, what is the balanced reduction half-reaction after the electrons in both half rea
Lostsunrise [7]

Answer :  The balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced redox reaction is :

Al(s)+Cu^{2+}(aq)\rightarrow Al^{3+}(aq)+Cu(s)

The half oxidation-reduction reactions are:

Oxidation reaction : Al\rightarrow Al^{3+}+3e^-

Reduction reaction : Cu^{2+}+2e^-\rightarrow Cu

In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

Oxidation reaction : 2Al\rightarrow 2Al^{3+}+6e^-

Reduction reaction : 3Cu^{2+}+6e^-\rightarrow 3Cu

The balanced redox reaction will be:

2Al(s)+3Cu^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Cu(s)

Thus, the balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

6 0
3 years ago
Other questions:
  • Which of the following does not describe elements?
    8·2 answers
  • Calculate the pH of a 0.60 M solution of NH3
    10·1 answer
  • a chemist studies two forms of refined gasoline. which of the following branches of chemistry might the chemist us?
    7·2 answers
  • What is solubility?
    14·2 answers
  • Xplain why the kidneys are important to our survival. (2 points)
    7·2 answers
  • Barb tests the properties of three minerals and makes a data table to record her results, as shown below.
    5·1 answer
  • A partir de 140 g de n2 y una cantidad de h2 se obtuvo 153G de NH³. Cual es el % de rendimiento de la reacción química
    9·1 answer
  • In parts of England during the 19th century, the peppered moth was widespread. This kind of moth comes in two color variations,
    12·2 answers
  • 18. What is one of the three things that cause the surface currents of the oceans?
    8·1 answer
  • The value of ka for weak acid is to 4.0x10^-5 what is degree of dissociation of the acid in aqueous solution of concentration 0.
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!