Hemoglobin has a much greater affinity for carbon monoxide than oxygen. In a hyperbaric chamber (containing high levels of oxygen) can treat carbon monoxide poisoning, by displacing carbon monoxide from Hemoglobin competitively.
Hemoglobin has a much greater affinity for carbon monoxide than oxygen. This is because, a coordinate bond is formed with Carbon monoxide and Haem structure of the hemoglobin.
Carbon monoxide with Hemoglobin is called as Carboxy haemoglobin.
Presence of oxygen displaces the Carbon monoxide with Hemoglobin that is formed due to poisoning.
Hyperbaric chamber is a chamber which contains pure oxygen in a chamber. The atmospheric pressure is kept about three to four times than the normal, such that the replacement of Carbon monoxide from Haem can occur as fast as possible since this reduces the half life of the Carboxy haemoglobin.
It is advisable not to treat Carbon monoxide poisoning yourself.
Hyperbaric oxygen is used to treat the following conditions as well:
- Infections
- Wounds
- Air bubble is blood
Learn more about Carbon Monoxide here, brainly.com/question/11313918
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Answer:
Radon
Explanation:
One element that will have similar property as an atom with 118 protons is Radon because it will belong to the p-block and the noble gas group.
The element will follow atomic number 117 which is already in the 7th group on the periodic table.
- Generally, on the periodic table, elements in the same group will have the same chemical property.
- The valency of most elements determines their chemical behavior.
- Since our mystery element is in the 8th group, noble gas group, it will mostly behave like any of the elements in the group.
Answer:
1. Two people stand on the same side of a large tire. Both people pull the tire with equal force.
2. an object’s ability to not change its motion
3. The car moves forward, while inertia keeps the balloon in place.
4. The unbalanced forces of air resistance and gravity slow the airplane and pull it down.
5. The force acting on the object must be unbalanced.
Answer:
V = 12.93 L
Explanation:
Given data:
Number of moles = 0.785 mol
Pressure of balloon = 1.5 atm
Temperature = 301 K
Volume of balloon = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values.
V = nRT/P
V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm
V = 19.4 L /1.5
V = 12.93 L
