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mel-nik [20]
3 years ago
14

1.A telescope is a tool that helps people observe distant objects. In the simplest telescope design, incoming light hits a lens

and is focused to a single point. This focused image is then magnified by a second lens so that it is roughly the same size as an observer's pupil. Which of the following wave behaviors plays the most important role in the functioning of this type of telescope?
Group of answer choices

reflection

resonance

refraction

interference

2.Pick the THREE statements that describe convex lenses.
Group of answer choices

They make the image of an object appear smaller.

Light rays spread out as they exit the lens.

They are thicker in the middle than at the ends

They make the image of an object appear larger.

They are thicker at the ends than in the middle.

Light rays converge as they exit the lens.
Chemistry
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

it is refraction

Explanation:

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_____________ is an acronym used to refer a family of iron alloys.
Daniel [21]

FeNi or NiFe is an acronym used to refer a family of iron alloys.

<h3>What is alloy?</h3>

An alloy is a mixture of chemical elements that contains at least one is a metal.

<h3>Alloy of iron</h3>

The alloy of iron-nickel can be abbreviated as FeNi, which implies iron-nickel.

where;

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Thus, FeNi or NiFe is an acronym used to refer a family of iron alloys.

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5 0
2 years ago
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

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