Question

A 21.496 grams sample of magnesium is burned in air to form magnesium oxide and magnesium nitride. When the products are treated with water,2.813 grams of gaseous ammonia are generated. Calculate the amounts of magnesium nitride and magnesium oxide formed?

Answer 1

25.898 g is the amount of magnesium nitride and magnesium oxide formed.

Step1 2Mg(s)+ O2(g)-----> 2 MgO(s)

3Mg(s)+N2(g)------> Mg3N2(s)

Mg3N2(s)+ 6 H2O(l)---> 3Mg(OH)2 + 2 NH3(g)

Step2 Moles of NH3 = (2.813/17)

Moles of Mg3N2= (1/2) Moles of NH3 = (2.813/2x17)= 2.813/34

Mass of Mg3N2 = (2.813/34) x100 =8.274g (Molar mass of Mg3N2=100)

Step3 Mass of Mg in Mg3N2 =(72/100) x8.274 =5.957g

Mass of Mg converted in MgO= 21.496-5.957=15.539

Moles of MgO= Moles of Mg = 15.539/24

Mass of MgO = 15.539x40/24 =25.898 g.

Magnesium is a cofactor for over 300 enzymatic systems that regulate various biochemical reactions in the body, including protein synthesis, muscle and nerve function, glycemic control, and blood pressure regulation [1-3].

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