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sergejj [24]
1 year ago
13

Project 1 Hypothesis Construction

Chemistry
1 answer:
alukav5142 [94]1 year ago
5 0

The hypothesis should be; "Increasing the amount of ice increases the rate at which the ice will melt"

<h3>What is a hypothesis?</h3>

The term hypothesis refers to a tentative explanation that could be applied in order to explain an observation. When we give a hypothesis, it must be subjected to rigorous experimentation thus it can be confirmed or repelled by experiment.

Now, we can see that the question here is; "How does the amount of salt added to ice affect the rate at which the ice will melt?" This implies that the correct hypothesis here ought to have to do with the impact of the amount of ice in the affirmative.

Thus, the hypothesis should be; "Increasing the amount of ice increases the rate at which the ice will melt"

Learn more about hypothesis:brainly.com/question/13025783

#SPJ1

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A solution of ethanol (c2h5oh) in water is prepared by dissolving 75.0 ml of ethanol (density 0.79 g/cm3 ) in enough water to ma
navik [9.2K]

Given the density of ethanol = 0.79\frac{g}{cm^{3} }

Volume of ethanol = 75.0 mL

Calculating the mass if ethanol from density and volume:

75.0 mL * \frac{0.79g}{1cm^{3} } *\frac{1cm^{3} }{1mL}=59.25g

Molar mass of ethanol = (2*atomic weight of C)+(6*atomic weight of H)+(1*atomic weight of O)

                                     =(2*12g.mol) + (6*1g/mol) + (1*16g/mol)

                                     =46g/mol

Moles of ethanol = 59.25 g *\frac{1 mol}{46g} =1.288 mol

Volume of the solution = 250.0 mL

Converting the volume from mL ot L:

250.0mL*\frac{1L}{1000mL}=0.2500L

Molarity of ethanol in the solution = \frac{1.288mol}{0.250L} =5.15 M

5 0
3 years ago
To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber
Phoenix [80]

Answer:

The volume of the gas at given temperature is 1300 cm^3

Explanation:

P_1 = initial pressure of gas = 1 atm

T_1 = initial temperature of gas = 0^oC=273.15 K

V_1 = initial volume of gas = 310 cm^3 = 310 mL = 0.310 L

(1 cm^3= 1mL , 1 mL = 0.001 L)

P_1V_1=nRT_1..[1]

P_2 = final pressure of gas = 2.1 atm

T_2 = final temperature of gas = 2,200^oC=273+2200 K=2473.15 K

V_2 = final volume of gas = ?

P_2V_2=nRT_2..[2]

By dividing [1] and [2] we get combined gas equation :,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

Now put all the given values in the above equation, we get:

V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}

V_2=1.3 L=1300 mL= 1300 cm^3

The volume of the gas at given temperature is 1300 cm^3

3 0
3 years ago
Read 2 more answers
There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the
mihalych1998 [28]
Remember that density refers to the "mass per unit volume" of an object.

So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.

In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is

As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

The effect on density would be that it would erroneously appear to be greater

Hope this helps!

Good luck
6 0
3 years ago
Relate the intermolecular forces in hydrocarbons to their physical properties and uses
DENIUS [597]

The physical properties of alkenes and alkynes are generally similar to those of alkanes or cycloalkanes with equal numbers of carbon atoms. Alkynes have higher boiling points than alkanes or alkenes, because the electric field of an alkyne, with its increased number of weakly held π electrons, is more easily distorted, producing stronger attractive forces between molecules.

8 0
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Which of these changes will increase the vapor pressure of water in a sealed container?
Vlad1618 [11]

Answer:

Option B

Explanation:

Salt is a non-volatile solute and hence adding salt will increase the boiling point of water and hence reduce the vapor pressure. While on the other hand, adding more water will require more time to boil and hence produce vapor and thus the vapor pressure. Shaking will also not help in increasing the vapor pressure. Thus, only increasing the temperature of the water will create more vapors at a faster rate and hence increase the vapor pressure.

Thus, option B is the correct answer

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2 years ago
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