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3 years ago

8

Rearrange the formula for mechanical energy to solve for height:

1 answer:

docker41 [41]3 years ago

4 0

Explanation:

Given formula:

ME= $\frac{1}{2}$ mv²+mgh

To make height the subject of the formula, follow the following procedures;

Subtract $\frac{1}{2}$ mv² from both side of equation

M.E - $\frac{1}{2}$ mv² = $\frac{1}{2}$ mv² - $\frac{1}{2}$ mv²+mgh

This gives:

M.E - $\frac{1}{2}$ mv² = mgh

Multiply both sides of the expression by $\frac{1}{mg}$

( M.E - $\frac{1}{2}$ mv² ) x $\frac{1}{mg}$ = $\frac{1}{mg}$ x mgh

h = ( M.E - $\frac{1}{2}$ mv² ) x $\frac{1}{mg}$

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

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jok3333 [9.3K]

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3 years ago

Read 2 more answers

a vehicle changes its velocity from 90 km/h to a dead stop in 10s. show that its acceleration in doing so is -2.5m/s^2

telo118 [61]

90000m/3600s = 25 m/s

a=0-25/10 ⇒ a = - 5/2 m/s^2

4 0

4 years ago

uring the investigation of a traffic accident, police find skid marks 89.9 m long. They determine the coefficient of friction be

aivan3 [116]

Answer:

$V_{0}=29.68m/s$

Explanation:

In order to solve this problem, we must first do a drawing of the situation (see attached picture).

When the brakes of the car were applied, we can see that there was only one horizontal force affecting the vehicle's movement, which was the force of friction. When analyzing the free body diagram we can apply Newton's laws to determine the equations we will use to solve this.

$\sum F_{x}=ma$

so:

-f=ma

we also know that:

$f=N\mu_{k}$

so

$-N\mu_{k}=ma$

we can now solve for the acceleration, so we get:

$a=\frac{-N\mu_{k}}{m}$

we don't know what the normal force is, so we can find it out by analyzing the vertical forces applied to the car:

$\sum F_{y}=0$

so we get:

N-W=0

which means that:

N=W

we also know that:

W=mg

so

N=mg

we can substitute this into the first equation so we get:

$a=\frac{-mg\mu_{k}}{m}$

which simplifies to:

$a=-g\mu_{k}$

we can now substitute the provided data:

$a=(-9.8m/s^{2})(0.5)$

which yields:

$a=-4.9m/s^{2}$

once we got the acceleration, we can use kinematics formulas to solve this, we got the following formula:

$a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}$

we know the final velocity must be zero, since that's where the car got to a stop, so the formula then becomes:

$a=-\frac{V_{0}^{2}}{2x}$

we can now solve for the initial velocity, which yields:

$V_{0}=\sqrt{-2xa}$

so we can now substitute the daa we know, so we get:

$V_{0}=\sqrt{-2(89.9m)(-4.9m/s^{2})}$

so we get:

$V_{0}=29.68m/s$

So from this we know that the velocity of the car must have been of at least 29.68m/s when the brakes were applied.

4 0

4 years ago

What is total revenue in economics

dsp73

Answer:

be more specific

Explanation:

4 0

3 years ago

Multiple Choice

Andreas93 [3]

Acceleration of car is 4m/s²

Acceleration of truck is 2m/s²

Explanation:

Given parameters:

Force on the car and truck = 12000N

Mass of car = 3000kg

Mass of truck = 6000kg

Unknown:

Acceleration of car = ?

Acceleration of truck = ?

Solution:

Force is product of mass and acceleration. It is a push or a pull exerted on a body.

Force = mass x acceleration

Make acceleration the subject of the formula;

Acceleration = $\frac{Force}{mass}$

Acceleration of car = $\frac{12000}{3000}$ = 4m/s²

Acceleration of truck = $\frac{12000}{6000}$ = 2m/s²

learn more:

Acceleration brainly.com/question/3820012

Newton's law brainly.com/question/11411375

#learnwithBrainly

3 0

3 years ago