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Crank
3 years ago
6

Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc

tor, with respect to the outer conductor, is +600 V. An electron is released from rest at the surface of the outer conductor. What is the speed of the electron as it reaches the inner conductor? (e = 1.60 × 10-19 C, m el = 9.11 x 10-31 kg, k = 1/4π ε0 = 8.99 × 109 N · m2/C2)
Physics
1 answer:
xxMikexx [17]3 years ago
3 0

Answer: 14.52*10^6 m/s

Explanation: In order to explain this problem we have to consider the energy conservation for the electron within the coaxial cylidrical wire.

the change in potential energy for the electron; e*ΔV is  equal to energy kinetic gained for the electron so:

e*ΔV=1/2*m*v^2  v^=(2*e*ΔV/m)^1/2= (2*1.6*10^-19*600/9.1*10^-31)^1/2=14.52 *10^6 m/s

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Arturiano [62]

Answer:

0.4

Explanation:

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Since the mass is moving with a constant velocity, there's no acceleration hence

F=Fr=\mu N where N is the weight of object and \mu is coefficient of kinetic friction.

F=\mu N and making [tex]\mu the subject

\mu=\frac {F}{N}

Substituting F for 8 N and N for 20 N

\mu=\frac {8}{20}=0.4

Therefore, coefficient of kinetic friction is 0.4

4 0
4 years ago
A circular dartboard has a radius of 2 meters and a red circle in the center. Assume you hit the target at a random point. For w
Sati [7]

Answer:

1.549 m

Explanation:

Given:

The radius of the circular board, r = 2 m

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Total area of the board = πr² = π × 2²

let the radius of the red area be R

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on substituting the value of the area, we have

0.6 = (πR²)/ (π × 2²)

or

R² = 2.4

or

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3 0
3 years ago
You drop a ball from a height of 32 meters how much time passes before the ball hits the ground
tankabanditka [31]

Answer:

31 seconds

Explanation:

ajsfhlAS

5 0
3 years ago
NEED ANSWERED ASAP!! will give brainliest!
kotegsom [21]
The kinetic energy of any moving object is

            K.E.  =  (1/2) (mass) (speed)² .
 
To use this simple formula, the 'mass' has to be in kilograms,
and the 'speed' has to be in meters-per-second. 

You can see that we have a slight problem that has to be cleaned up:
The speed in the question is given in "kilometers per hour", but we'll
need it in "meters per second".  So let's convert that right now: 

       (600 km/hour) x (1 hour / 3600 seconds) x (1000 meters / km)

    =    (600 x 1 x 1000 / 3600)    (km-hour-meters / hour-second-km)

    =              166.67  meters/second .

Now we're ready to plug numbers into the formula for K.E.

                  (1/2) (mass) (speed)²

            =    (1/2) (80,000 kg) (166.67 m/s)²

            =           (40,000 kg) (27,777.8 m²/s²)

            =                1,111,111,111  kg-m²/s²

            =                 1.1... x 10⁹  Joules   (choice D) 

8 0
3 years ago
Resistance and resistivity are related by a:
kondor19780726 [428]

Answer: D

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R = (rho × L)/A

Where

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rho = resistivity = proportionality constant which depends on the quality of the wire.

Therefore, Resistance and resistivity are related by a:

proportionality constant dependent on the identity of the material.

4 0
3 years ago
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