Answer:
0.535 atm
Explanation:
Since the volume of the tank is constant, we use Gay- Lussac's law to find the pressure at 180°C.
So, P₁/T₁ = P₂/T₂ where P₁ = pressure at S.T.P = 1 atm, T₁ = temperature at S.T.P = 273.15 K, P₂ = pressure of gas at 180 °C and T₂ = 180 °C = 273.15 + 180 K = 453.15 K
So, P₁/T₁ = P₂/T₂
P₂ = P₁T₂/T₁
Substituting the values of the variables into the equation, we have
P₂ = P₁T₂/T₁
P₂ = 1 atm × 453.15 K/273.15 K
P₂ = 1 atm × 1.66
P₂ = 1.66 atm
We now need to find the total number of moles of each gas present
number of moles of nitrogen = mass of nitrogen, m/molar mass of nitrogen molecule M
n = m/M
m = 2.5 g and M = 2 × atomic mass of nitrogen (since it is diatomic) = 2 × 14 g/mol = 28 g/mol
So, n = 2.5 g/28 g/mol
n = 0.089 mol
number of moles of chlorine, n' = mass of chlorine, m'/molar mass of chlorine molecule M'
n' = m'/M'
m' = 13.3 g and M = 2 × atomic mass of chlorine (since it is diatomic) = 2 × 35.5 g/mol = 71 g/mol
So, n' = 13.3 g/71 g/mol
n' = 0.187 mol
So, the total number of moles of gas present is n" = n + n' = 0.089 mol + 0.187 mol = 0.276 mol
So, the partial pressure due to nitrogen gas, P = mole fraction of nitrogen × pressure of gas at 180 °C
P = n/n" × P₂
P = 0.089 mol/0.276 mol × 1.66 atm
P = 0.322 × 1.66 atm
P = 0.535 atm
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