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3 years ago

X = v xo t. x = (10.0 m/s)(3.53 s) x = ????

Physics

2 answers:

LenaWriter [7]3 years ago

7 0

x = V<em>x</em> * t

given V<em>x</em> = 10m/s n t = 3.53s

x = 10 * 3.53

= 35.3m

labwork [276]3 years ago

7 0

The equation given is confusing: x = v xo t. But given x = (10.0 m/s)(3.53 s), I think x = (10.0 m/s)(3.53 s) = 35.3m

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marusya05 [52]

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Explanation:

According to law of conservation of momentum, the momentum of the bodies before collision is equal to the momentum of the bodies after collision. Since the second body was initially at rest this means the initial velocity of the body is "zero".

Let m1 and m2 be the masses of the bodies

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Since momentum = mass × velocity

The conservation of momentum of the body will be

m1u1 + m2u2 = (m1+m2)v

Note that the body will move with a common velocity (v) after collision which will serve as the velocity of each object after collision.

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Therefore the velocity of each object after the collision is 6.67cm/s

b) kinectic energy of the 10.0g object will be 1/2MV²

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kinectic energy of the 5.0g object will be 1/2MV²

= 1/2×5×6.67²

= 222.44Joules

= 111.22Joules

Fraction of the initial kinetic transferred to the 10g object will be

111.22/222.44

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3 years ago

A 1000.0 kg truck accelerates from 20.0 m/s to 25.0 m/s over a distance of 300.0 m. What is the average net force on the truck?

choli [55]

Answer:

The average net force on the truck is 375 Newtons.

Explanation:

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u = initial velocity = 20 m/s

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Using Newton's second law, we have:

F=m×a

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3 years ago

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Andrei [34K]

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Explanation:

First, the Hamster eats the carrot, then the hamster is getting chemical energy.

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3 years ago

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Since the two forces act in the same direction, this means that we can simply add their magnitudes to find the net combined force on the barge. Therefore, we get

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