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VLD [36.1K]
3 years ago
15

A new planet is discovered that has twice the Earth's mass and twice the Earth's radius. On the surface of this new planet a per

son who weights 500 N on Earth would experience a gravitational force of ______.
(A) 125 N
(B) 250 N
(C) 500 N
(D)) 1000 N
(E) 2000 N
Physics
1 answer:
Margarita [4]3 years ago
8 0

Answer:

option B

Explanation:

Radius of new planet,R' = 2R

Mass of the earth, M' = 2 M

R and M is the Radius and Mass of the earth.

Weight of the person on earth = 500 N

Weight of the person in the new planet = ?

We know acceleration due to gravity is calculated by using formula

   g = \dfrac{GM}{R^2}

now, acceleration due to gravity on the new planet

   g' = \dfrac{GM'}{R'^2}

   g' = \dfrac{G(2M)}{(2R)^2}

   g' =\dfrac{1}{2} \dfrac{GM}{R^2}

   g' =\dfrac{g}{2}

here acceleration due to gravity is half in new planet, so weight will also be half on the new planet.

Weight on the new plane is equal to \dfrac{500}{2} = 250 N

correct answer is option B

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A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result
Virty [35]

Hello!

A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision

We have the following data¹:

ΔP (momentum before impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 5 m/s

mB (mass) = 5 kg

vB (velocity) = 0 m/s

Solving:

ΔP = mA*vA + mB*vB

ΔP = 10 kg*5 m/s + 5 kg*0 m/s

ΔP = 50 kg*m/s + 0 kg*m/s

Δp = 50 kg*m/s ← (momentum before impact)

We have the following data²:

ΔP (momentum after impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 0 m/s

mB (mass) = 5 kg

vB (velocity) = 10 m/s

Solving:

Δp = mA*vA + mB*vB

Δp = 10 kg*0 m/s + 5 kg*10 m/s

Δp = 0 kg*m/s + 50 kg*m/s

Δp = 50 kg*m/s ← (momentum after impact)

*** Then, which principle explains the result ?

Law of conservation of momentum, <u>since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.</u>

Note:  Bodies of different masses and velocities may have the same kinetic energy, if proportionality between the units is maintained it can occur that they have the same kinetic energy.

Answer:

B) law of conservation of momentum

_______________________

\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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Answer:

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Explanation:

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square both sides to get 2.25 = 2\pi ( L/9.81)

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Answer:

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Explanation:

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