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Marat540 [252]
3 years ago
13

A flare is shot from a snowmobile with an initial velocity of 4.3 m/s at 90*, while the snowmobile is moving at 8.5 m/s at 0.0*.

Determine using both methods, graphical and mathematical, the initial net velocity (magnitude and direction) of the flare. HOW DO I DO THIS??
Physics
1 answer:
Sedaia [141]3 years ago
8 0

The driver is tooling along in his snowmobile, pointed north,
at 8.5 m/s.

He's carrying the flares with him, so the flares are also moving north
at 8.5 m/s.

When he fires the flare straight up, it has a vertical velocity of 4.3 m/s
straight up, and a horizontal velocity of 8.5 m/s towards the north.

The magnitude of the net velocity is √(4.3² + 8.5²) .
That's about  9.53 m/s, at some angle between straight up
and straight north.

The angle above horizontal is the angle that has a tangent of  4.3/8.5 .
I'll let you work out the angle.
 
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In 1996, astronomers discovered an icy object beyond pluto that was given the designation 1996 tl 66. it has a semimajor axis of
antoniya [11.8K]

Answer : 2446 years.

Explanation :

Length of semi major axis is, a=84\ au= 1.496\times 10^{11}\ m

According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.

i.e T^2=\dfrac{4\pi^2}{GM}a^3

where G is gravitational constant

M is  mass of sun, M=1.98\times 10^{30}\ Kg

So, T^2=\dfrac{4\times (3.14)^2}{6.6\times 10^{-11}Nm^2/Kg\times 1.98\times 10^{30}\Kg}

T^2=3\times 10^{-19}\times(84\times 1.496\times 10^{11})^3

T^2=3\times 10^{-19}\times 1984415.6\times 10^{33}

T^2=59532469.8\times 10^{14}\ s

T=7715.7\times 10^7\ s

since, 1\ sec=3.17\times 10^{-8}\ years

So, orbital period is approximately 2446 years.

7 0
4 years ago
After a nucleus undergoes radioactive decay, its new mass number is:
Ivanshal [37]
Radioactive "decay" means particles and stuff shoot OUT of a nucleus.
After that happens, there's less stuff in the nucleus than there was before.
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7 0
4 years ago
Read 2 more answers
Suppose you had the same laser and diffraction grating from the previous question but now you had a flat detection screen. You w
kolezko [41]

Answer:

measuring the zero intensity point, we can deduce the movement of the screen.

The distance from the center of the pattern to the first zero is proportional to the distance to the screen,

Explanation:

The expression for the diffraction phenomenon is

           a sin θ = m λ

for the case of destructive interference. In general the detection screen is quite far from the grid, let's use trigonometry to find the angles

           tan θ = y / L

     

in these experiments the angles are small

          tan θ = sin θ / cos θ = sin θ

          sunt θ = y / L

we substitute

          a \frac{y}{L}= m  λ

           y = m L λ / a

therefore, by carefully measuring the zero intensity point, we can deduce the movement of the screen.

 

The distance from the center of the pattern to the first zero is proportional to the distance to the screen, so you can know where the displacement occurs, it should be clarified that these displacements are very small so the measurement system must be capable To measure quantities on the order of hundredths of a millimeter, a micrometer screw could be used.

4 0
3 years ago
A 0.45-kilogram football traveling at a speed of 22 meters per second is caught by an 84-kilogram stationary receiver. if the fo
Troyanec [42]

Impulse = Change in momentum.  
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3 0
3 years ago
What happens to gravitational potential energy as a roller coaster moves down a hill?
Kaylis [27]
It is converted to kinetic energy.
5 0
4 years ago
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