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Mamont248 [21]
3 years ago
12

For two acids of equal concentration, the stronger acid has —

Chemistry
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0
The for this question is A

forsale [732]3 years ago
6 0

Answer:

C

Explanation:

it has to have hydroniums

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What is the ph of a solution that has a poh of 11.24
galina1969 [7]
Always remember that pH + pOH = 14 
Here, you have a pOH of 11.24, so  you replace it in the equation, and u get:
pH + 11.24 = 14

Then, You move 11.24 to the other part. and moving from a part to another change the sign of the equation. And you get:
pH = 14 - 11.24 = 2.76

So, the pH of a solution that has a pOH of 11.24 is pH = 2.76

Hope this Helps :)
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3 years ago
Why are there 2 chloride ions for every 1 calcium in calcium chloride
tensa zangetsu [6.8K]

Answer:

See explanation

Explanation:

Calcium is divalent. This means that it donates two electrons during ionic bond formation. Since chlorine atom can only accept one electron during ionic bond formation, two chlorine atoms must accept the two electrons donated by calcium.

For this purpose, each time CaCl2 is formed, there must be two chlorine atoms for each calcium atom.

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Thirsty Thursday:) post your celebrity crush <br> Or post your favorite drink :)
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Answer:

My celebrity crush is young Keanu Reeves and my favorite drink is matcha tea

Explanation:

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3 years ago
Definition of electron
Whitepunk [10]

Answer: a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

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Read 2 more answers
A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this
erastova [34]

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the <em>PV=nRT </em>formula, where:

  • P = 2.4 atm
  • V = 250 mL ⇒ 250 / 1000 = 0.250 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 15 °C ⇒ 15 + 273 = 288 K

We <u>input the given data</u>:

  • 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And <u>solve for n</u>:

  • n = 0.025 mol

Finally we <u>calculate how many particulates are there in 0.025 moles</u>, using <em>Avogadro's number</em>:

  • 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates
6 0
3 years ago
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