312.3 let me know if i’m right?
<span>The first ionization
energy is the energy that is obligatory in order to eliminate the first
electron from an atom(neutral) in the GAS phase
, the second ionization energy is defined as the
energy required to remove the second electron from an atom(+1 ion) in the GAS phase.
</span>the third ionization energy is the energy it takes to remove an electron from a 2+ ion. (That means that the atom has already lost two electrons, you are now removing the third.)
<span> Ionization energy will normally increase for every electron that is removed and
increases from left to right in the periodic table and moving up the periods
hope it helps</span>
Answer : The shape of the fluoroform molecule is Tetrahedral.
Explanation :
First we have to calculate the Hybridization of the molecule by formula,
![\text{Number of electrons} = \frac{1}{2}[V+H-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5BV%2BH-C%2BA%5D)
where,
V = Number of valence shell electron in central atom
H = Number of neighboring monovalent atom
C = charge of cation
A = charge of anion
The central atom in this molecule is Carbon, it has 4 electrons in their valence shell.
The neighboring monovalent atoms are one Hydrogen atom and three Fluorine atom.
There is no charge of cation and anion on the given molecule.
V = 4
H = 1 Hydrogen atom + 3 fluorine atom = 4
C = 0
A = 0
By the above hybridization formula, we get
= 4
The number of electron pair = 4
The number of lone pair = 0
The number of electrons is 4, this means that the hybridization is
and the geometry of the molecule is Tetrahedral.
The geometry of the molecule is shown below.
In order to purify ammonia to high purity, two basic methods are used. The older one consists in passing gaseous ammonia containing 80 ppm of impurities under atmospheric pressure through liquid ammonia with dissolved metallic sodium.