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Sunny_sXe [5.5K]
3 years ago
14

(27ax^3 – 9a^2x) ÷ 3ax PLEASE DO NOT INCLUDE PARENTHESES IN YOUR ANSWER

Mathematics
1 answer:
qaws [65]3 years ago
4 0
Divide each term in the parentheses by 3ax 

this gives 9x^2 - 3a
You might be interested in
Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?
lilavasa [31]
We have the following function:
 f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
 We note that the function depends on x because it is f (x).
 However, there is no variable x in the function.
 Therefore we can assume that the function is constant, since:
 a = constant
 b = constant
 Therefore, the degree of the function is zero
 Answer:
 
The function is zero degree.
7 0
3 years ago
If someone could explain this to me that be really great :p
BigorU [14]
"x" always goes on the left side and "y" always goes on the right side of the parentheses. If you only have an "x" then you will just put a zero in for "y" and vice versa. I hope this helps.
4 0
3 years ago
Restless Leg Syndrome and Fibromyalgia
mixas84 [53]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}\\\\=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=0.183333\\\\\approx 0.1833

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

6 0
3 years ago
How would you go on dividing 7/893​
love history [14]

Answer:

0.00783874

Step-by-step explanation:

7/893= 0.00783874

I just put it in the calculator  

3 0
4 years ago
Use the digits 0-9, find out how many 4 digit numbers can be configured based on the stated conditions:
Alexeev081 [22]
A) On the first place we can put 9 digits, on the second 9, on the third place 8 and on the last place 7 ( because no digits can be repeated ):
9 · 9 · 8 · 7 =4536 numbers
b) There are 5 odd digits can be repeated. So:
5 · 10 · 10 · 5 = 2500 numbers
c) On the first place we can put:5,6,7,8,9 (5 digits) On the last place is just one (0), because the number must be divisible by 10:
5 · 10 · 10 · 1 = 500 numbers
d) on the first place we can put 2 digits ( 1, or 2 - there are no 4-digit numbers starting with 0). The last digit must be even, but the order can be:
X - odd - odd - even           2 · 5 · 4 ·  5 = 200
X - odd - even - even         2 · 5  · 5 · 4 = 200
X - even - odd - even         2 · 5  · 5 · 4 = 200
X - even - even - even       2 · 5 ·  4 · 3 = 120 
Finally: 200+ 200 + 200 + 120 = 720 numbers
3 0
3 years ago
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