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siniylev [52]
3 years ago
10

A solution of AgNO3 contains 29.66 g of solute in 100.0 mL of solution. What is the molarity of the solution

Chemistry
1 answer:
Julli [10]3 years ago
6 0

Answer:

1.7 M

Explanation:

Given data:

Mass of AgNO₃ = 29.66 g

Volume of solution = 100 mL (100/1000 = 0.1 L)

Molarity of solution = ?

Solution;

Number of moles of AgNO₃:

Number of moles = mass/ molar mass

Number of moles = 29.66 g/ 169.87 g/mol

Number of moles = 0.17 mol

Molarity of solution:

Molarity =  moles of solute / volume of solution in L

Molarity = 0.17 mol / 0.1 L

Molarity = 1.7 M

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The concentration of hydrogen peroxide solution can be determined by
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The question is incomplete, the complete reaction equation is;

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Answer:

2.275 M

Explanation:

The equation of the reaction is;

2 MnO4^-(aq) + 16 H^+(aq) + 5H2O2(aq) -------> 2Mn^+(aq) + 10H^+ (aq) + 8H2O(l)

Let;

CA= concentration of MnO4^- =  0.0187 mol dm–3

CB = concentration of H2O2 = ?

VA = volume of MnO4^- = 24.35 cm3

VB = volume of H2O2 = 25.0 cm3

NA = number of moles of  MnO4^- = 2

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From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.0187 * 24.35 * 5/25.0 * 2

CB = 0.0455 M

Since  

C1V1 = C2V2

C1 = initial concentration of H2O2 solution = ?

V1 = initial volume of H2O2 solution =  5.0 cm3

C2 = final concentration of H2O2 solution= 0.0455 M

V2 = final volume of H2O2 solution = 250 cm3

C1 = C2V2/V1

C1 = 0.0455 * 250/5

C1 = 2.275 M

8 0
3 years ago
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