What is the time required for an object starting from rest.

Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2

siniylev [52]

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg $^{o} C$ ), $T_{2}$ = $69.2^{o}$ and $T_{1}$ = $31.7^{o}$ .

So that,

Q = mc( $T_{2}$ - $T_{1}$ )

= 96.7 x 0.874 x ( $69.2^{o}$ - $31.7^{o}$ )

= 96.7 x 0.874 x 37.5

= 3169.3425

Q = 3169.34

= 3.2 KJ

The amount of energy required is 3169.34 Joules.

8 0

2 years ago

The nucleus of any atom requires a strong force to hold it together. This strong force is required because

astra-53 [7]

Answer:

<h2>The answer is.............................................................................................................................................................C</h2>

Explanation:

4 0

3 years ago

a skier starts at rest at the top of a hill with 350 J of gravitational potential energy. Assuming energy is conserved, what is

spayn [35]

Answer:

350Joules

Explanation:

According to law of Conservation of energy, the amount of energy at the used up at the start is equal to that at the end.

The initial energy used up is gravitational potential energy

Final energy at the lowest point is kinetic energy.

If the energy is conserved then it means energy is not used up during the process hence;

Initial Potential energy = Final kinetic energy

If the gravitational potential energy is 350Joules then her final kinetic energy at the lowest point will also be 350Joules

3 0

3 years ago

To practice problem-solving strategy 26.1 resistors in series and parallel. two bulbs are connected in parallel across a source

hichkok12 [17]

Emf e = 11
r 1 = 3.0
r 2 = 3.0
r 3 = ?

The two in parallel are equivalent to 3 • 3/6 = 1.5 Ω
To have 2.4 volts across them, the current is I = 2.4/1.5 = 1.6 amps. and the unknown R = (11–2.4) / 1.6 = 5.375 Ω or 5.4 Ω

3 0

3 years ago

An Atwood machine consists of two masses, mA = 6.8 kg and mB = 8.0 kg , connected by a cord that passes over a pulley free to ro

Lisa [10]

To solve this problem it is necessary to apply the concewptos related to Torque, kinetic movement and Newton's second Law.

By definition Newton's second law is described as

F= ma

Where,

m= mass

a = Acceleration

Part A) According to the information (and as can be seen in the attached graph) a sum of forces is carried out in mass B, it is obtained that,

$\sum F = m_b a$