Answer:
u = 11.6 m/s
Explanation:
The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.
Maximum height, H = 10.9
Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :
u = 11.6 m/s
So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.
Lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students. Option D is correct.
<h3>
What is a Transverse wave?</h3>
- The wave in which the oscillation of particles is is perpendicular to the direction of energy transfer.
- The students can make a transverse wave by raising their hands up and then down, one student at a time.
- The raised hand represents the oscillation of particles while the sequence of the raising hand represents the direction of energy transfer.
Therefore, lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students.
Learn more about Transverse waves:
brainly.com/question/3813804
Answer:
65
Explanation:
The resonant frequencies for a fixed string is given by the formula nv/(2L).
Where n is the multiple
.
v is speed in m/s
.
The difference between any two resonant frequencies is given by v/(2L)= fn+1 – fn
fundamental frequency means n=1
i.e fn+1 – fn = 390 -325
= 65
The question is a little confusing. An electromagnetic wave is radiation. One doesn’t emit the other. Take another look at the question and write it again please.
