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MissTica
3 years ago
12

There are 30 students in a class. Choose the statement that best explains why at least two students have last names that begin w

ith the same letter. Multiple Choice
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are more than 2 students in the class.
Using the pigeonhole principle, in any class of 30 students there must be exactly two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are more than 2 letters in the alphabet.
Engineering
1 answer:
galben [10]3 years ago
4 0

Answer:

Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.

Explanation:

The pigeonhole principle states that if k+1 objects are placed in l holes, there must be at-least one hole where more than one objects are placed. So is the case with the first letter of last names of 30 students as there are only 26 unique alphabets in English language.

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You want to plate a steel part having a surface area of 160 with a 0.002--thick layer of lead. The atomic mass of lead is 207.19
Pepsi [2]

Answer:

<u><em>To answer this question we assumed that the area units and the thickness units are given in inches.</em></u>

The number of atoms of lead required is 1.73x10²³.    

Explanation:

To find the number of atoms of lead we need to find first the volume of the plate:

V = A*t

<u>Where</u>:

A: is the surface area = 160

t: is the thickness = 0.002

<u><em>Assuming that the units given above are in inches we proceed to calculate the volume: </em></u>

V = A*t = 160 in^{2}*0.002 in = 0.32 in^{3}*(\frac{2.54 cm}{1 in})^{3} = 5.24 cm^{3}    

Now, using the density we can find the mass:

m = d*V = 11.36 g/cm^{3}*5.24 cm^{3} = 59.5 g

Finally, with the Avogadros number (N_{A}) and with the atomic mass (A) we can find the number of atoms (N):

N = \frac{m*N_{A}}{A} = \frac{59.5 g*6.022 \cdot 10^{23} atoms/mol}{207.19 g/mol} = 1.73 \cdot 10^{23} atoms    

Hence, the number of atoms of lead required is 1.73x10²³.

I hope it helps you!

3 0
3 years ago
Find the current Lx in the figure
AleksandrR [38]

Explanation:

\frac{1}{8}  +  \frac{1}{2}   \\ 1.6 + 1.4 = 3 \\  \frac{1}{3}  +  \frac{1}{9}   \\ 2.25 + 2 = 4.25 \: ohm

R total = 4.25 ohm

I total = Vt/Rt

I total= 17/4.25= 4 A

Ix= 600 mA

\frac{9}{9 + 3}  \times 4 = 3\\   \frac{2}{2 + 8} \times 3 = 0.6a \\  = 0.6 \: milli \: amper

6 0
3 years ago
Check the level of motor oil in your engine by ?
Usimov [2.4K]

Answer:

cpct gvxjjxjhdfjokjdzfjiyddzzsjhxf

6 0
2 years ago
3. (a) (5 points) Suppose N packets arrive simultaneously to a link at which no packets are currently being transmitted or queue
Bezzdna [24]

Answer:

(N-1) × (L/2R) = (N-1)/2

Explanation:

let L is length of packet

R is rate

N is number of packets

then

first packet arrived with 0 delay

Second packet arrived at = L/R

Third packet arrived at = 2L/R

Nth packet arrived at = (n-1)L/R

Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R

Now

L / R = (1000) / (10^6 ) s = 1 ms

L/2R = 0.5 ms

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4 0
3 years ago
The weatherman states that the current temperature is 95 F and the dew point is 74 F. What is the current relative humidity?
spayn [35]

Answer:

Current Relative Humidity is 29.623

Given:

Current Temperature, T_{c} = 95 F = 35^{\circ}C

Dew point temperature, T_{d} = 74 F = 23.34^{\circ}C

Solution:

Now, in order to calculate the Relative Humidity, RH, we use the given formula:

T_{d} =100( \frac{\frac{aT_{c}}{b + T}b + lnRH}{a - \frac{aT_{c}}{b + T} + lnRH})

where

a = 17.625

b = 237.7

Now, using the above formula and given values:

23.34 = (237.7\frac{\frac{17.625\times 35}{ 237.7 + 35} + lnRH}{17.625 - \frac{17.625\times 35}{237.7 + 35} + lnRH})

23.34(17.625 - 2.26 + lnRH) = (237.7\times 2.26 + lnRH)

358.62 + 23.34lnRH) = (537.20 + lnRH)

358.62 + 23.34lnRH) = (537.20 + lnRH)

On solving the above eqn, we get:

RH = 29.623

3 0
3 years ago
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