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MissTica
3 years ago
12

There are 30 students in a class. Choose the statement that best explains why at least two students have last names that begin w

ith the same letter. Multiple Choice
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are more than 2 students in the class.
Using the pigeonhole principle, in any class of 30 students there must be exactly two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are more than 2 letters in the alphabet.
Engineering
1 answer:
galben [10]3 years ago
4 0

Answer:

Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.

Explanation:

The pigeonhole principle states that if k+1 objects are placed in l holes, there must be at-least one hole where more than one objects are placed. So is the case with the first letter of last names of 30 students as there are only 26 unique alphabets in English language.

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Determine whether w is in the span of the given vectors v1; v2; : : : vn
Brrunno [24]

Determine whether w is in the span of the given vectors v1; v2; : : : vn

. If your answer is yes, write w as a linear combination of the vectors v1; v2; : : : vn and  enter the coefficients as entries of the matrix as instructed is given below

Explanation:

1.Vector to be in the span means means that it contain every element of said vector space it spans. So if a set of vectors A spans the vector space B, you can use linear combinations of the vectors in A to generate any vector in B because every vector in B is within the span of the vectors in A.

2.And thus v3 is in Span{v1, v2}. On the other hand, IF all solutions have c3 = 0, then for the same reason we may never write v3 as a sum of v1, v2 with weights. Thus, v3 is NOT in Span{v1, v2}.

3.In the theory of vector spaces, a set of vectors is said to be linearly dependent if at least one of the vectors in the set can be defined as a linear combination of the others; if no vector in the set can be written in this way, then the vectors are said to be linearly independent.

4.Given a set of vectors, you can determine if they are linearly independent by writing the vectors as the columns of the matrix A, and solving Ax = 0. If there are any non-zero solutions, then the vectors are linearly dependent. If the only solution is x = 0, then they are linearly independent.

7 0
3 years ago
Suppose there are 93 packets entering a queue at the same time. Each packet is of size 4 MiB. The link transmission rate is 1.4
Ghella [55]

Answer:

0.19s

Explanation:

Queueing delay is the time a job waits in a queue before it can be executed. it is the difference in time betwen when the packet data reaches it destination and the time when it was executed.

Queueing delay =(N-1) L /2R

where N = no of packet =93

L = size of packet = 4MB

R = bandwidth = 1.4Gbps = 1×10⁹ bps

4 MB = 4194304 Bytes

(93 - 1)4194304 / 2× 10⁹

queueing delay =192937984 ×10⁻⁹

=0.19s

5 0
3 years ago
Tech A says that bench bleeding a master cylinder will prevent having to bleed air from the brake lines during replacement. Tech
cupoosta [38]

Answer:

  Tech B

Explanation:

Bleeding the master cylinder on the bench does nothing for the air in the brake lines on the vehicle. The bench bleeding is a preferred first step, but bleeding the rest of the brake system is also required. A final check of proper operation on the vehicle should also be accomplished.

Tech B is correct.

6 0
3 years ago
A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500
lukranit [14]

Answer:

The resulting strain is 1.39\times 10^{-3}.

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

\epsilon=\dfrac{F}{AE}

E is elastic modulus of Cu is are of cross section

\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}

So, the resulting strain is 1.39\times 10^{-3}.

6 0
4 years ago
11. Amphetamines that keep drivers awake also help with coordination and reaction time.
RSB [31]

Answer:

O B false

Explanation:

dont do drugs

5 0
3 years ago
Read 2 more answers
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