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MissTica
3 years ago
12

There are 30 students in a class. Choose the statement that best explains why at least two students have last names that begin w

ith the same letter. Multiple Choice
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are more than 2 students in the class.
Using the pigeonhole principle, in any class of 30 students there must be exactly two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.
Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are more than 2 letters in the alphabet.
Engineering
1 answer:
galben [10]3 years ago
4 0

Answer:

Using the pigeonhole principle, in any class of 30 students there must be at least two students who have last names that begin with the same letter since there are only 26 letters in the alphabet.

Explanation:

The pigeonhole principle states that if k+1 objects are placed in l holes, there must be at-least one hole where more than one objects are placed. So is the case with the first letter of last names of 30 students as there are only 26 unique alphabets in English language.

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Explanation:

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\frac{v-u}{a} =t\\\\Making \ v\ the \ subject\ of\ formula:\\\\First \ cross-multiply:\\\\v-u=at\\\\add\ u\ to \ both\ sides:\\\\v-u+u=at+u\\\\v=u+at

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\frac{y-x^2}{x}=3z\\ \\Making\ y\ the\ subject\ of\ formula:\\\\First \ cross \ multiply:\\\\y-x^2=3xz\\\\y=3xz+x^2\\\\y=x(x+3z)

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x=y+xy\\\\Making\ x\ the\ subject\ of\ formula:\\\\Subtract\ xy\ from \ both\ sides:\\\\x-xy=y+xy-xy\\\\x-xy=y\\\\x(1-y)=y\\\\Divide\ through\ by \ 1-y\\\\\frac{x(1-y)}{1-y} =\frac{y}{1-y}\\ \\x=\frac{y}{1-y}

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ay^2=x^3\\\\Make\ y\ the\ subject\ of\ formula:\\\\Divide\ through\ by\ a:\\\\y^2=\frac{x^3}{a}\\ \\Take\ square\ root\ of\ both\ sides:\\\\y=\sqrt{\frac{x^3}{a}} \\

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