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SVETLANKA909090 [29]
2 years ago
12

Consider a mixture of oil and water. What terms would you use to describe this mixture? Check all that apply. Heterogeneous homo

geneous immiscible miscible.
Chemistry
2 answers:
GenaCL600 [577]2 years ago
6 0

A mixture of oil and water is:

Heterogeneous

immiscible

<h3>What type of mixture of oil and water is?</h3>

The water molecules attract each other, and the oil molecules stick together. That causes oil and water to form two separate layers. Water molecules pack closer together, so they sink to the bottom, leaving oil sitting on top of the water. The mixture can be called as Emulsion. It is an immiscible liquid and the mixture is heterogeneous as oil floats on top of water surface but do not mix with it.

Thus, correct options are Heterogeneous and immiscible.

Find more information about Mixture here:

brainly.com/question/498370

irina [24]2 years ago
5 0

Answer:

Its A and C

Explanation:

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. What is the mass of 23.56 moles of Glucose<br> ples of Glucose - C6H1206?
GaryK [48]

Answer:

4244.48 g to the nearest hundredth.

Explanation:

The molar mass of Glucose = 6*12.011 + 12*1.008+ 6*15.999

= 180.156.

So 23.56 moles = 180.156 * 23.56 =  4244.48 g

8 0
3 years ago
What is the element with period 2 group 14
Ghella [55]

Answer:

Carbon

Explanation:

7 0
3 years ago
Read 2 more answers
The sample concentration was measured at 50mg/ml. The loading concentration needs to be 10mg/ml. The final volume needs to be 25
Svet_ta [14]

Answer:

a)  V_1=5ul

b)  v=20ul

Explanation:

From the question we are told that:

initial Concentration C_1=50mg/ml

Final Concentration C_2=10mg/ml

Final volume needs V_2 =25ul

Generally the equation for Volume is mathematically given by

C_1V_1=C_2V_2

V_1=\frac{C_1V_1}{C_2}

V_1=\frac{10*25}{50}

V_1=5ul

Therefore

The volume of buffer needed is

v=V_2-V_1\\\\v=25-5

v=20ul

3 0
2 years ago
Use the following data to estimate ΔHf° for magnesium fluoride. Mg(s) + F2(g) → MgF2(s) lattice energy −2913 kJ/mol first ioniza
miss Akunina [59]

Answer:

The correct answer is -1085 KJ/mol

Explanation:

To calculate the formation enthalphy of a compound by knowing its lattice energy, you have to draw the Born-Haber cycle step by step until you obtain each element in its gaseous ions. Find attached the correspondent Born-Haber cycle.

In the cycle, Mg(s) is sublimated (ΔHsub= 150 KJ/mol) to Mg(g) and then atoms are ionizated twice (first ionization: ΔH1PI= 735 KJ/mol, second ionization= 1445 KJ/mol) to give the magnesium ions in gaseous state.

By other hand, the covalent bonds in F₂(g) are broken into 2 F(g) (Edis= 154 KJ/mol) and then they are ionizated to give the fluor ions in gaseous state 2 F⁻(g) (2 x ΔHafinity=-328 KJ/mol). The ions together form the solid by lattice energy (ΔElat=-2913 KJ/mol).

The formation enthalphy of MgF₂ is:

ΔHºf= ΔHsub + Edis + ΔH1PI + ΔH2PI + (2 x ΔHaffinity) + ΔElat

ΔHºf= 150 KJ/mol + 154 KJ/mol + 735 KJ/mol + 1445 KJ/mol + (2 x (-328 KJ/mol) + (-2913 KJ/mol).

ΔHºf= -1085 KJ/mol

3 0
3 years ago
Convert 5.0x10^24 molecules to liters.
Over [174]
To convert the given value we need conversion factors to relate molecules to liters. At STP, we know that 1 mol is equal to 22.4 L  and by using Avogadro's number we can relate molecules to 1 mol. Calculation is as follows:

5.0x10^24 molecules ( 1 mol / <span>6.022 x 10^23 molecules<span> ) ( 22.4 L / 1 mol) = 186.0 L </span></span>
3 0
3 years ago
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