All categories

3 years ago

Particle motion in surface waves is __________ motion.

Physics

2 answers:

Alexxandr [17]3 years ago

8 0

The particle motion in surface waves is a combination of longitudinal and transverse motion.

Further Explanation:

According to the vibration of the particle, the waves are classified into two categories:

Transverse Waves

Longitudinal waves

Transverse Waves:

The transverse waves are the waves in which the motion of the wave particle is perpendicular to the direction of motion of the waves.

Example: The electromagnetic waves, vibrations produced in a guitar string etc.

Longitudinal waves:

The longitudinal waves are the waves in which the motion of the wave particle is along the direction of propagation of the wave.

Example: Sound waves, seismic waves etc.

The waves produces on the surface are considered to be the combination of the transverse as well as the longitudinal waves because during its motion on the surface, the wave particles vibrate perpendicular to the surface as well as along the direction of propagation of the wave.

Thus, the particle motion in surface waves is a combination of longitudinal and transverse motion.

Learn More:

1. What is the threshold frequency ν0 of cesium brainly.com/question/6953278

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s brainly.com/question/1979815

3. What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays brainly.com/question/9059731

Answer details:

Grade: High School

Subject: Physics

Physics: Waves

Keywords:

Transverse, longitudinal, combination, waves, surface waves, along, perpendicular, propagation, electromagnetic, surface of water.

gulaghasi [49]3 years ago

7 0

<h3>Answer;</h3>

B.)neither longitudinal nor transverse

<h3>Explanation;</h3>

Longitudinal waves are waves in which the vibration of particles is parallel to the direction of the wave motion.
Transverse waves on the other hand are those waves in which the vibration of particles is perpendicular to the direction of the wave motion.
In surface waves particles in the medium of transmission move in a circular motion. Therefore, they are neither transverse waves nor longitudinal waves.

You might be interested in

Distance = 6 km south 60 minutes What was the average velocity

blsea [12.9K]

v = x/t

v = average velocity, x = displacement, t = elapsed time

Given values:

x = 6km south, t = 60min

Plug in and solve for v:

v = 6/60

v = 0.1km/min south

3 0

3 years ago

Read 2 more answers

An object starts from rest, and accelerates at 2m/s2 for 10s. How far has it gone in that time

blagie [28]

Answer:

100m

Explanation:

$s = ut + \frac{1}{2} a {t}^{2}$

u=0;t=10sec;a=2m/s²

$s = 0(10) + \frac{1}{2}(2 \times {10}^{2} )$

s=10²;100m

7 0

4 years ago

To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t

QveST [7]

Answer:

Explanation:

From the work-energy theorem, the workdone by a force on a body causes a change in kinetic energy of the body.

But, remember that the work done (W) by a force (F) on a body is the product of the force and the distance d, moved by the body caused by the force. i.e

W = F x d

This distance is a measure of the position of the body at a given instance.

Therefore, the work done is given by the force as a function of distance (or position).

3 0

3 years ago

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

GaryK [48]

Mary and her younger brother Alex decide to ride the carousel at the State Fair, Mary's and Alex's angular speed M and tangential speed vM is mathematically given as

Mary's and Alex's angular speed=1.43

Tangential speed mary=3.22 m/s

Tangential speed alex =2.260m/s

<h3>What is Mary's and Alex's angular speed M and tangential speed vM?</h3>

Generally, the equation for angular speed is mathematically given as

$w=2\pi /T\\\\Therefore\\\\w=2\pi/3.9$

w = 1.61 rev/see 3.9

Centripetal acc mary = v^2/r

Centripetal acc mary = w^2r

Centripetal acc mary = w^2x 2m

Centripetal acc. of Alex = w²x L.u

Therefore

$\frac{(ac) mary }{(ac) plex}= 1.43$

Hence

tang. speed V=Wr

tang. speed of mary = 1.61x2 = 3.22 m/s

tang. speed of Alex: 1.61X1·4 =2.260m/s