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2 years ago

Particle motion in surface waves is __________ motion.

Physics

2 answers:

Alexxandr [17]2 years ago

8 0

The particle motion in surface waves is a combination of longitudinal and transverse motion.

Further Explanation:

According to the vibration of the particle, the waves are classified into two categories:

Transverse Waves

Longitudinal waves

Transverse Waves:

The transverse waves are the waves in which the motion of the wave particle is perpendicular to the direction of motion of the waves.

Example: The electromagnetic waves, vibrations produced in a guitar string etc.

Longitudinal waves:

The longitudinal waves are the waves in which the motion of the wave particle is along the direction of propagation of the wave.

Example: Sound waves, seismic waves etc.

The waves produces on the surface are considered to be the combination of the transverse as well as the longitudinal waves because during its motion on the surface, the wave particles vibrate perpendicular to the surface as well as along the direction of propagation of the wave.

Thus, the particle motion in surface waves is a combination of longitudinal and transverse motion.

Learn More:

1. What is the threshold frequency ν0 of cesium brainly.com/question/6953278

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s brainly.com/question/1979815

3. What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays brainly.com/question/9059731

Answer details:

Grade: High School

Subject: Physics

Physics: Waves

Keywords:

Transverse, longitudinal, combination, waves, surface waves, along, perpendicular, propagation, electromagnetic, surface of water.

gulaghasi [49]2 years ago

7 0

<h3>Answer;</h3>

B.)neither longitudinal nor transverse

<h3>Explanation;</h3>

Longitudinal waves are waves in which the vibration of particles is parallel to the direction of the wave motion.
Transverse waves on the other hand are those waves in which the vibration of particles is perpendicular to the direction of the wave motion.
In surface waves particles in the medium of transmission move in a circular motion. Therefore, they are neither transverse waves nor longitudinal waves.

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Intrinsic impedance of media 2 = 125.68 ohms

Check the explanation section for a better understanding

Explanation:

a) Wavelength of the incident wave in air

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Speed of light in air, c = 3 * 10⁸ Hz

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Wavelength of the incident wave in medium 2

The refractive index of air in the lossless dielectric medium:

$n = \sqrt{\epsilon_{r} } \\n = \sqrt{9 }\\n =3$

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b) Intrinsic impedances of media 1 and media 2

The intrinsic impedance of media 1 is given as:

$n_1 = \sqrt{\frac{\mu_0}{\epsilon_{0} } }$

Permeability of free space, $\mu_{0} = 4 \pi * 10^{-7} H/m$

Permittivity for air, $\epsilon_{0} = 8.84 * 10^{-12} F/m$

$n_1 = \sqrt{\frac{4\pi * 10^{-7} }{8.84 * 10^{-12} } }$

$n_1 = 377 \Omega$

The intrinsic impedance of media 2 is given as:

$n_2 = \sqrt{\frac{\mu_r \mu_0}{\epsilon_r \epsilon_{0} } }$

Permeability of free space, $\mu_{0} = 4 \pi * 10^{-7} H/m$

Permittivity for air, $\epsilon_{0} = 8.84 * 10^{-12} F/m$

ϵr = 9

$n_2 = \sqrt{\frac{4\pi * 10^{-7} *1 }{8.84 * 10^{-12} *9 } }$

$n_2 = 125.68 \Omega$

c) The reflection coefficient,r and the transmission coefficient,t at the boundary.

Reflection coefficient, $r = \frac{n - n_{0} }{n + n_{0} }$

You didn't put the refractive index at the boundary in the question, you can substitute it into the formula above to find it.

$r = \frac{3 - n_{0} }{3 + n_{0} }$

Transmission coefficient at the boundary, t = r -1

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Maximum amplitudes in the total field is given by:

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