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3 years ago

Particle motion in surface waves is __________ motion.

Physics

2 answers:

Alexxandr [17]3 years ago

8 0

The particle motion in surface waves is a combination of longitudinal and transverse motion.

Further Explanation:

According to the vibration of the particle, the waves are classified into two categories:

Transverse Waves

Longitudinal waves

Transverse Waves:

The transverse waves are the waves in which the motion of the wave particle is perpendicular to the direction of motion of the waves.

Example: The electromagnetic waves, vibrations produced in a guitar string etc.

Longitudinal waves:

The longitudinal waves are the waves in which the motion of the wave particle is along the direction of propagation of the wave.

Example: Sound waves, seismic waves etc.

The waves produces on the surface are considered to be the combination of the transverse as well as the longitudinal waves because during its motion on the surface, the wave particles vibrate perpendicular to the surface as well as along the direction of propagation of the wave.

Thus, the particle motion in surface waves is a combination of longitudinal and transverse motion.

Learn More:

1. What is the threshold frequency ν0 of cesium brainly.com/question/6953278

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s brainly.com/question/1979815

3. What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays brainly.com/question/9059731

Answer details:

Grade: High School

Subject: Physics

Physics: Waves

Keywords:

Transverse, longitudinal, combination, waves, surface waves, along, perpendicular, propagation, electromagnetic, surface of water.

gulaghasi [49]3 years ago

7 0

<h3>Answer;</h3>

B.)neither longitudinal nor transverse

<h3>Explanation;</h3>

Longitudinal waves are waves in which the vibration of particles is parallel to the direction of the wave motion.
Transverse waves on the other hand are those waves in which the vibration of particles is perpendicular to the direction of the wave motion.
In surface waves particles in the medium of transmission move in a circular motion. Therefore, they are neither transverse waves nor longitudinal waves.

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3 years ago

A 1.00 kg block of ice, at -25.0°C, is warmed by 35 kJ of energy. What is the final temperature of the ice?

ahrayia [7]

Answer:

-8.4°C

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3 years ago

For a wire has a circular cross section with a radius of 1.23mm.

Mila [183]

Answer:

$5.731\times 10^{-5}\ m/s$

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = $1.6\times 10^{-19}\ C$

n = Conduction electron density in copper = $8.49\times 10^{28}\ electrons/m^3$

$v_d$ = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

$I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s$

The drift speed of the electrons is $5.731\times 10^{-5}\ m/s$

$v_d=\dfrac{I}{neA}$

From the equation we can see the following

$v_d\propto \dfrac{1}{n}$

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3 years ago

A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu

zlopas [31]

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

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