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nlexa [21]
3 years ago
13

The current price per share of corporate mutual fund is 14.35

Engineering
2 answers:
frosja888 [35]3 years ago
6 0
14.22 should be the correct answer
ololo11 [35]3 years ago
4 0
The right answer is 14,22 but if I had to choose one from here it would be the nearliest, 14,24.
the operation is: 14,35/1,009=14,22202
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Depending on the environmental demands, there are different types of organizational structures, including __________.
Andrews [41]

Answer:

  • Functional (Centralized) Organization
  • Divisional Organization
  • Team-Based Organization
  • Product-Based Organization
  • Modular Organization
  • Matrix Organization

Explanation:

Organization structure:

refers to the idea of how people are supposed to work and coordinate in an organization to maintain a healthy and effective work environment.

There are various types of organizational structures which depends on several factors. There is no single best organization structure. Each structure has its own advantages and disadvantages. In order to select a structure the organization's vision, mission, culture values, goals are to be identified first.

6 0
3 years ago
2. An aluminum (E = 70 GPa) tube of length 8-m is used as a simply supported column carrying a 1.2 kN axial load. If the outer d
STALIN [3.7K]

Answer:

1211 N.

Explanation:

Okay, we are given the following data or parameters or information in the question above;

=> "aluminum (E = 70 GPa) tube of length 8-m.

=> "The aluminum is used as a simply supported column carrying a 1.2 kN axial load"

The axial load to provide a factor of safety of 2 against buckling =[ (22/7)^2 × 224348 × 1000 × 70] ÷ (8 × 1000)^2 × 2.

The axial load to provide a factor of safety of 2 against buckling = 1211 N.

7 0
3 years ago
A flat rectangular door in a mine is submerged froa one side in vater. The door dimensions are 2 n high, 1 n vide and the vater
julsineya [31]

Answer:

Force on the bolt = 24.525 kN

Force on the 1st hinge = 8.35 kN

Force on the 2nd hinge = 16.17 kN

Explanation:

Given:

height = 2 m

width =1 m

depth of the door from the water surface = 1.5 m

Therefore,

\bar{y} =1.5+1 = 2.5 m

Hydrostatic force acting on the door is

F= \rho \times g\times \bar{y}\times A

F= 1000 \times 9.81\times 2.5\times 2\times 1

         = 49050 N

         = 49.05 kN

Now finding the Moment of inertia of the door about x axis

I_{xx}=\frac{1}{12}\times b\times h^{3}

I_{xx}=\frac{1}{12}\times1\times 2^{3}

               = 0.67

Now location of force, y^{*}

y^{*}=\bar{y}+\frac{I_{xx}}{A\times \bar{y}}

y^{*}=2.5+\frac{0.67}{2\times 1\times 2.5}

             = 2.634

Therefore, calculating the unknown forces

F=F_{A}+R_{B}+R_{C} = 49.05  ------------------(1)

Now since \sum M_{R_{A}}=0

∴ R_{B}\times L+R_{C}\times L-F\times \frac{1}{2}=0

  R_{B}+R_{C}-F\times \frac{1}{2}=0

  R_{B}+R_{C}=\frac{F}{2}

  R_{B}+R_{C}=24.525        -----------------------(2)

From (1) and (2), we get

R_{A} = 49.05-24.525

                = 24.525 kN

This is the force on the Sliding bolt

Taking \sum M_{R_{C}}=0

F\times 0.706-R_{A}\times 0.84-R_{B}\times 1.68 = 0

49.05\times 0.706-24.525\times 0.84-R_{B}\times 1.68 = 0

R_{B} =8.35 kN

This is the reaction force on the 1st hinge.

Now from (1), we get

R_{C} =16.17 kN

This is the force on the 2nd hinge.

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3 years ago
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