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enyata [817]
3 years ago
6

A kernel-level thread wishes to acquire a mutex lock declared as global in the process. True or False: the function call used be

low causes the thread to block at this point, if the mutex lock is already acquired by a different thread. int resultcode -pthread mutex_trylock (myMutex);
True
False
Engineering
1 answer:
Alik [6]3 years ago
7 0

Answer:

  1. A kernel-level thread wishes to acquire a mutex lock declared as global in the process.  <u>"</u><u>True"</u>  
  2. The function call used below causes the thread to block at this point, if the mutex lock is already acquired by a different thread. int resultcode -pthread mutex_trylock (myMutex). <u>"False"</u>                              

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Are routers better for internet connection rather than a WiFi modem?
sleet_krkn [62]

Answer:

Depends

Explanation:

The modem connects you to the Internet via ISP. Without a modem, your router will only allow you to connect to a LAN. A modem will provide connections for just a single wired device. If you want to go wireless you need a router.

8 0
4 years ago
Read 2 more answers
A flywheel made of Grade 30 cast iron (UTS = 217 MPa, UCS = 763 MPa, E = 100 GPa, density = 7100 Kg/m, Poisson's ratio = 0.26) h
hram777 [196]

Answer:

N = 38546.82 rpm

Explanation:

D_{1} = 150 mm

A_{1}= \frac{\pi }{4}\times 150^{2}

              = 17671.45 mm^{2}

D_{2} = 250 mm

A_{2}= \frac{\pi }{4}\times 250^{2}

              = 49087.78 mm^{2}

The centrifugal force acting on the flywheel is fiven by

F = M ( R_{2} - R_{1} ) x w^{2} ------------(1)

Here F = ( -UTS x A_{1} + UCS x A_{2} )

Since density, \rho = \frac{M}{V}

                        \rho = \frac{M}{A\times t}

                        M = \rho \times A\times tM = 7100 \times \frac{\pi }{4}\left ( D_{2}^{2}-D_{1}^{2} \right )\times t

                        M = 7100 \times \frac{\pi }{4}\left ( 250^{2}-150^{2} \right )\times 37

                        M = 8252963901

∴ R_{2} - R_{1} = 50 mm

∴ F = 763\times \frac{\pi }{4}\times 250^{2}-217\times \frac{\pi }{4}\times 150^{2}

  F = 33618968.38 N --------(2)

Now comparing (1) and (2)

33618968.38 = 8252963901\times 50\times \omega ^{2}

∴ ω = 4036.61

We know

\omega = \frac{2\pi N}{60}

4036.61 = \frac{2\pi N}{60}

∴ N = 38546.82 rpm

7 0
4 years ago
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Answer:

B- extreme fit, close fit, adjustable fit

Explanation:

A human-fit design typically involves the process of manufacturing or producing products (tools) that are easy to use by the end users. Therefore, human-fit designs mainly deals with creating ideas that makes the use of a particular product comfortable and convenient for the end users.

The design for human-fit strategies include; extreme fit, close fit and adjustable fit.

Hence, when the aforementioned strategies are properly integrated into a design process, it helps to ensure the ease of use of products and guarantees comfort for the end users.

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3 years ago
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Answer:

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3 years ago
Question 1 A design team completes their high-fidelity prototype of a responsive website. Before they hand off designs to the en
MissTica

A question the design team should answer before handing off the designs is: are the designs a true representation of the intended end user experience?

<h3>What is a website?</h3>

A website can be defined as a collective name that is used to describe series of webpages that are interconnected or linked together with the same domain name.

In Computer technology, the main goal of a high-fidelity prototype is to understand how end users would interact with a website and areas to improve the design.

In conclusion, the design team should answer whether or not the designs are a true representation of the intended end user experience before handing off the designs.

Read more on website here: brainly.com/question/26324021

5 0
2 years ago
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