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enyata [817]
3 years ago
6

A kernel-level thread wishes to acquire a mutex lock declared as global in the process. True or False: the function call used be

low causes the thread to block at this point, if the mutex lock is already acquired by a different thread. int resultcode -pthread mutex_trylock (myMutex);
True
False
Engineering
1 answer:
Alik [6]3 years ago
7 0

Answer:

  1. A kernel-level thread wishes to acquire a mutex lock declared as global in the process.  <u>"</u><u>True"</u>  
  2. The function call used below causes the thread to block at this point, if the mutex lock is already acquired by a different thread. int resultcode -pthread mutex_trylock (myMutex). <u>"False"</u>                              

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2. A well of 0.1 m radius is installed in the aquifer of the preceding exercise and is pumped at a rate averaging 80 liter/min.
hodyreva [135]

Question:

The question is not complete. See the complete question and the answer below.

A well that pumps at a constant rate of 0.5m3/s fully penetrates a confined aquifer of 34 m thickness. After a long period of pumping, near steady state conditions, the measured drawdowns at two observation wells 50m and 100m from the pumping well are 0.9 and 0.4 m respectively. (a) Calculate the hydraulic conductivity and transmissivity of the aquifer (b) estimate the radius of influence of the pumping well, and (c) calculate the expected drawdown in the pumping well if the radius of the well is 0.4m.

Answer:

T = 0.11029m²/sec

Radius of influence = 93.304m

expected drawdown = 3.9336m

Explanation:

See the attached file for the explanation.

8 0
3 years ago
A fatigue test was conducted in which the mean stress was 46.2 MPa and the stress amplitude was 219 MPa.
sleet_krkn [62]

Answer:

a)σ₁ = 265.2 MPa

b)σ₂ = -172.8 MPa

c)Stress\ ratio =-0.65

d)Range = 438 MPa

Explanation:

Given that

Mean stress ,σm= 46.2 MPa

Stress amplitude ,σa= 219 MPa

Lets take

Maximum stress level = σ₁

Minimum stress level =σ₂

The mean stress given as

\sigma_m=\dfrac{\sigma_1+\sigma_2}{2}

2\sigma_m={\sigma_1+\sigma_2}

2 x 46.2 =  σ₁ +  σ₂

 σ₁ +  σ₂ = 92.4 MPa    --------1

The amplitude stress given as

\sigma_a=\dfrac{\sigma_1-\sigma_2}{2}

2\sigma_a={\sigma_1-\sigma_2}

2 x 219 =  σ₁ -  σ₂

 σ₁ -  σ₂ = 438 MPa    --------2

By adding the above equation

2  σ₁ = 530.4

σ₁ = 265.2 MPa

-σ₂ = 438 -265.2 MPa

σ₂ = -172.8 MPa

Stress ratio

Stress\ ratio =\dfrac{\sigma_{min}}{\sigma_{max}}

Stress\ ratio =\dfrac{-172.8}{265.2}

Stress\ ratio =-0.65

Range = 265.2 MPa - ( -172.8 MPa)

Range = 438 MPa

8 0
3 years ago
Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m^
Nat2105 [25]

Answer:

The answer is "\bold{ 259.2 \times 10^{11} }".

Explanation:

The amount of kilograms, which travel in a thick sheet of hydrogen:

M= -DAt \frac{\Delta C}{ \Delta x} \\\\

D =1.0 \times 10^{8} \ \ \ \frac{m^2}{s} \\\\ A = 0.20 \ m^2\\\\t = 1\ \ h = 3600 \ \   sec \\\\

calculating the value of \Delta C:

\Delta C =C_A -C_B

  = 2.4 - 0.6 \\\\    = 1.8 \ \ \frac{kg}{m^3}

calculating the value of \Delta X:

\Delta x = x_{A} -x_{B}

     = 0 - (5\ mm) \\\\ = - 5 \ \ mm\\\\= - 5 \times 10^{-3} \ m

M = -(1.0 \times 10^{8}  \times 0.20 \times 3600 \times  (\frac{1.8}{-5 \times 10^{-3}})) \\\\

    = -(1.0 \times 10^{8}  \times 720 \times  (\frac{1.8}{-5 \times 10^{-3}})) \\\\= -(1.0 \times 10^{8}  \times \frac{ 1296}{-5 \times 10^{-3}})) \\\\= (1.0 \times 10^{8}  \times 259.2 \times 10^3)) \\\\= 259.2 \times 10^{11} \\\\

3 0
3 years ago
A thin plastic membrane is used to separate helium from a gas stream. Under steady-state conditions the concentration of helium
Juli2301 [7.4K]

Answer:

N_A=1.5*10^-8 kmol/s.m^2

Explanation:

<u>KNOWN: </u>

Molar concentration of helium at the inner and outer surfaces of a plastic membrane. Diffusion coefficient and membrane thickness.  

<u>FIND:</u>

Molar diffusion flux.  

<u>ASSUMPTIONS:</u>

(1) Steady-state conditions, (2) One-dimensional diffusion in a plane wall, (3) Stationary medium, (4) Uniform C = C_A + C_B.  

<u>ANALYSIS:</u> The molar flux may be obtained from

 N_A=D_AB/L(C_A,1-C_A,2)

       =10^-9 m^2/s/0.001 m(0.02-0.005)kmol/m^3

N_A=1.5*10^-8 kmol/s.m^2

<u>COMMENTS:</u> The mass flux is:

n_A,x=M_a*N_A,x

n_A,x=6*10^-8 kg/s m^2

5 0
3 years ago
A. Imagine the white car in the left lane is moving more slowly than the surrounding traffic. How is this a violation of a state
asambeis [7]

The roads have pre-described lanes that should follow a particular speed and rules. When a driver drives slowly than he makes the other drivers impatient.

<h3>What are traffic rules?</h3>

Traffic rules are the regulations that are defined to regulate the vehicles and other conveyances that walk on the road. They are different in various places and have separate punishments for not following them.

The left lane of the road is generally for the drivers who want to pass by the vehicle ahead by following the mph rule. If the driver drives slowly then they make the other people impatient and result in honking.

Therefore, the driver driving slowly in the left lane makes others impatient.

Learn more about traffic rules here:

brainly.com/question/6034089

#SPJ2

4 0
2 years ago
Read 2 more answers
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