(a) The pitcher must throw the ball at 27.7 m/s
The momentum of an object is given by:

where
m is the mass of the object
v is the object's velocity
Let's calculate the momentum of the bullet, which has a mass of
m = 2.70 g = 0.0027 kg
and a velocity of

Its momentum is:

The pitcher must throw the baseball with this same momentum. The mass of the ball is
m = 0.146 kg
So the velocity of the ball must be

So, the pitcher must throw the ball at 27.7 m/s.
(b) a. The bullet has greater kinetic energy
The kinetic energy of an object is given by

where m is the mass of the object and v is its speed.
For the bullet, we have:

For the ball:

So, the bullet has greater kinetic energy.
Considering that the grasshopper starts on the ground and lands on the ground, there is no change in elevation. The range of the grasshopper is given by: <span>R=<span><span><span>v2</span>sin2θ</span>g</span></span>
If we now take the information that this is a maximal distance, the maximum range is given when the angle of launch is 45 degrees. This yields the equation: <span><span>R<span>max</span></span>=<span><span>v2</span>g</span></span>
We know R_max=0.4 m and g=9.8 m/s^2, so we can solve for v: <span>v=1.98m/s</span>
We are asked for the horizontal component, which by trigonometry is: <span><span>vx</span>=vcosθ</span>
We again take our angle of launch as 45 degrees and arrive at: <span><span><span>vx</span>=1.40m/s</span></span>
A
<span>(Volatile liquids, liquids with a high vapor pressure or low boiling point) </span>
Answer: Metallic bonds between tin ions cause a sheet of tin to be malleable
Explanation:
Hi!
givens: initial velocity = 0 m/s
time = 8.5 s
acceleration = 10 m/s^2
Unknown: displacement, velocity final
Equation:
Displacement = 1/2 (at^2) + viT
SS:
Displacement = 1/2 (10 * 8.5^2) + 0
Displacement = 361.25 m in a positive direction.
My math might be a little off, but I'm not sure...
But yeah! Hope this helped :)