All categories

3 years ago

An object is moving along a straight line. The graph shows the velocity of the object over

Physics

2 answers:

iren [92.7K]3 years ago

8 0

Answer:

From 9 to 10 sec the velocity is decreasing at a constant rate.

Change in V = 20 m/s - 30 m/s = -10 m/s

Since acceleration is constant from point E to point F (straight line)

and t = 9.5 sec is on this line

a = (20 m/s - 30 m/s) / 1 sec = -10 m/s^2

IRISSAK [1]3 years ago

4 0

Answer:

stupidddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddalllllllllllllllllllllllllllllllllllllllllllliiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiwantttttttttttttttttttttttttttttttttttttttttttttisssssssssssssssssssssssssssssssssssssssssssssspointtsssssssssssssssssssssssssssssssssssssssssssssssssssssssssajajajajajajajajajaj

Explanation:

You might be interested in

0.0884 moles of a diatomic gas

Sloan [31]

Answer:

W = - 118.24 J (negative sign shows that work is done on piston)

Explanation:

First, we find the change in internal energy of the diatomic gas by using the following formula:

$\Delta\ U = nC_{v}\Delta\ T$

where,

ΔU = Change in internal energy of gas = ?

n = no. of moles of gas = 0.0884 mole

Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)

Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K

ΔT = Rise in Temperature = 18.8 K

Therefore,

$\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J$

Now, we can apply First Law of Thermodynamics as follows:

$\Delta\ Q = \Delta\ U + W$

where,

ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)

W = Work done = ?

Therefore,

$-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\$

W = - 118.24 J (negative sign shows that work is done on piston)

7 0

3 years ago

Read 2 more answers

A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/

larisa [96]

Answer:

Total momentum, p = 21.24 kg-m/s

Explanation:

Given that,

Mass of first piece, $m_1=200\ g= 0.2\ kg$

Mass of the second piece, $m_2=300\ g= 0.3\ kg$

Speed of the first piece, $v_1=82\ m/s$ (along x axis)

Speed of the second piece, $v_2=45\ m/s$ (along y axis)

To find,

The total momentum of the two pieces.

Solve,

The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.

$p_x=m_1v_1$

$p_x=0.2\ kg\times 82\ m/s$

$p_x=16.4\ kg-m/s$

$p_y=m_2v_2$

$p_y=0.3\ kg\times 45\ m/s$

$p_y=13.5\ kg-m/s$

The net momentum is given by :

$p=\sqrt{p_x^2+p_y^2}$

$p=\sqrt{16.4^2+13.5^2}$

p = 21.24 kg-m/s

Therefore, the total momentum of the two pieces is 21.24 kg-m/s.

4 0

3 years ago

This diagram represents the synthesis of nitrogen monoxide. Write a balanced equation of this chemical reaction. A) N2(g) + O2(g

ruslelena [56]

The only balanced equation is B.

If you look at the equation and break it down you can see that in:

$N_{2} + O_{2}$ → $2NO$

Starting from the left side of the equation there are 2 Nitrogen atoms, and 2 oxygen atoms as indicated by the subscript.

To balance the equation, the number of atoms of each element in the right side equation should be equal to left. By putting the numerical coefficient of 2, you will distribute that to each element. So you will end up with 2 nitrogen atoms and 2 oxygen atoms on the left side of the equation. Thus, the equation is balanced.

The answer again, is B.

4 0

3 years ago

Read 2 more answers

True/False: If an object stays still, but the observer moves, the Doppler Effect is still observered

Vladimir79 [104]

Well, Harry, what you said is not necessarily true the way you said it.
But we know what you mean, and what you meant to say is true.

The Doppler effect is observed if there is relative radial motion
between an object and an observer AND if the object happens
to be putting out sound or light in the observer's direction.

3 0

3 years ago

Read 2 more answers

When two systems in contact are not at the same temperature, _____ occurs.

Korvikt [17]

The answer is "heat transfer."

6 0

3 years ago