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2 years ago

An object is moving along a straight line. The graph shows the velocity of the object over

Physics

2 answers:

iren [92.7K]2 years ago

8 0

Answer:

From 9 to 10 sec the velocity is decreasing at a constant rate.

Change in V = 20 m/s - 30 m/s = -10 m/s

Since acceleration is constant from point E to point F (straight line)

and t = 9.5 sec is on this line

a = (20 m/s - 30 m/s) / 1 sec = -10 m/s^2

IRISSAK [1]2 years ago

4 0

Answer:

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Explanation:

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How do I convert 498.82 cg to mg

mezya [45]

Answer:
498.82 cg is equivalent to 4988.2 mg

Explanation:
cg stands form centigrams
mg stands for milligrams

From the standards of conversion, to convert from centi to milli, we multiply the amount ny 10

This means that:
1 centigram = 10 milligram

To convert 498.82 cg to mg, all we have to do is cross multiplication as follows:
1 cg ..................> 10 mg
498.82 cg .........> ?? mg

498.82 cg = $\frac{498.82*10}{1}$ = 4988.2 mg

Hope this helps :)

3 0

3 years ago

Read 2 more answers

At which latitude would tropical rain forests be most likely?

Natasha_Volkova [10]

-60 degrees north north north

6 0

3 years ago

In a microwave oven, electrons describe circular motion in a magnetic field within a special tube called amagnetron; as you'll l

QveST [7]

Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

Explanation:

Given that,

Diameter = 2.62 mm

Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

$B=\dfrac{2\pi mf}{e}$

Where, f = frequency

e = charge of electron

Put the value into the formula

$B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}$

$B=0.077\ T$

(B). We need to calculate the energy of electron

Using formula of energy

$E=\dfrac{1}{2}m(r\omega)^2$

$E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2$

$E=1.4249\times10^{-16}\ J$

The energy in eV

$1 eV=1.6\times10^{-16}\ J$

$E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}$

$E=0.8906\ eV$

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

5 0

3 years ago

Which form of heat transfer occurs when objects of two temperatures touch

Arada [10]

Conducting because it occurs when two objects touch and heat is transferred

7 0

3 years ago

A very long string (linear density 0.7 kg/m ) is stretched with a tension of 70 N . One end of the string oscillates up and down

rewona [7]

To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by

$V = \sqrt{\frac{T}{\rho}}$