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Arisa [49]
3 years ago
9

Light reflected from a glass surface is polarized along the plane perpendicular to the glass surface. Please select the best ans

wer from the choices provided t f
Physics
1 answer:
leva [86]3 years ago
7 0

I believe it would be true not 100% sure


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What is a precipitate?
Lunna [17]
Rain is considered a precipitate. Along with: drizzle, sleet, snow and hail.

hope this helps :)

7 0
3 years ago
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The windshield of a car has a total length of arm and blade of 9 ​inches, and rotates back and forth through an angle of 93degre
Sergio039 [100]

Answer:

The area of the portion of the windshield cleaned by the 7-in wiper blade is 62.49 in²

Explanation:

Given

Length of blade = 9 inches

Angle of rotation = 93°

We're to calculate the area of the portion of the windshield cleaned by the 7​-in wiper​ blade?

We'll solve this by using area of a sector.

Area of a sector = ½r²θ

where θ is in radians.

So, angle of rotation (93°) must first be converted to radians

Converting 93º to radians, we get 31π/60

The area of the region swept out by the wiper blade = (area of the sector where r = 9 and

θ = 31π/60) - (area of the sector where r = (9-7) and θ = 31π/60).

We're making use of 9-7 because that region is outside the boundary of the 7in blade

So Area = ½*9²*31π/60 - ½*2²*31π/60

Area = ½*31π/60(9²-7²)

Area = 31π/120 * (81 - 49)

Area = 31π/120 * 32

Area = 992π/120

Area = 62.49151386765697 in²

Area ≈ 62.49 in²

Hence, the area of the portion of the windshield cleaned by the 7-in wiper blade is 62.49 in²

5 0
3 years ago
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A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t
BaLLatris [955]
Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

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3 years ago
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1<br> Verify the identity. Show your work.<br><br> cot θ ∙ sec θ = csc θ
Fittoniya [83]
To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ 
sec θ = 1 / cos <span>θ
csc </span>θ = 1 / sin θ<span>

Using these identities:
</span>cot θ ∙ sec θ = (cos θ / sin θ ) (<span> 1 / cos </span><span>θ)
</span>
We can cancel out cos <span>θ, leaving us with
</span>cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc <span>θ</span>
6 0
3 years ago
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