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dmitriy555 [2]
3 years ago
8

What are the three properties of gas

Chemistry
2 answers:
ArbitrLikvidat [17]3 years ago
7 0
1) they are easy to compress
2) they will expend to fill their container
3) They occupy more space then the liquids and solids they originated from.
MArishka [77]3 years ago
4 0
Gas water and ice i think bro
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3. What causes hydrogen bonding?
Fudgin [204]
Hydrogen bonding occurs between a hydrogen atom and an electronegative atom (e.g., oxygen, fluorine, chlorine). The bond is weaker than an ionic bond or a covalent bond, but stronger than van der Waals forces (5 to 30 kJ/mol). A hydrogen bond is classified as a type of weak chemical bond.
5 0
3 years ago
Read 2 more answers
Find the volume of 3.011x1023 molecules of O2 at STP.
lord [1]

Answer:

6.022 x 1023 molecules = 1 Mole O2 = 22.4L

3.022 x 1023 molecules = 1/2 Mole O2 = 11.2L

The answer is 11.2 Litres

Explanation:

8 0
2 years ago
3. Classify the chemical reaction shown here:
dolphi86 [110]

Answer:

A or D because the chemical reaction is long

5 0
3 years ago
Identify the oxidising and reducing agents in these reactions, by looking at the gaming and loss of ovygen.
Maru [420]

Answer:

A is oxidation . B is reduction

Explanation:

A will be oxidation agent because there is gain of

electrons

B will be reducing agent because there is loss of

electrons.

6 0
2 years ago
Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum
zhuklara [117]

Answer:

The volume of nitrogen oxide formed is 35.6L

Explanation:

The reaction of nitric acid with copper is:

Cu(s) + 4HNO₃ → Cu(NO₃)₂ + 2NO₂(g) + 2H₂O(l)

Moles of copper are:

4.95cm^3\frac{8.95g}{1cm^3} \frac{1mol}{63.55g} = 0.697 moles

Moles of nitric acid are:

230mL\frac{1.42g}{mL} \frac{68g}{100g} \frac{1mol}{63.01g}=3.52moles

As 1 mol of Cu reacts with 4 moles of HNO₃:

0.697 mol Cu × (4mol HNO₃ / 1mol Cu) = 2.79 moles of HNO₃ will react. That means Cu is limiting reactant.

Moles of NO₂ produced are:

0.697 mol Cu × (2mol NO₂ / 1mol Cu) = <em>1.394 moles of NO₂</em>

Using PV = nRT

<em>Where P is pressure (735torr / 760 = 0.967atm); n are moles (1.394mol); R is gas constant (0.082atmL/molK); T is temperature (28.2°C + 273.15 = 301.35K). </em>

Thus, volume is:

V = nRT / P

V = 1.394mol×0.082atmL/molK×301.35K / 0.967atm

V = 35.6L

<em>The volume of nitrogen oxide formed is 35.6L</em>

3 0
3 years ago
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