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Leona [35]
3 years ago
6

The conservation laws, show iftte-te​

Physics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

Explanation:

In physics, a conservation law states that a particular measurable property of an isolated physical system does not change as the system evolves over time. The exact conservation laws include conservation of energy, and conservation of linear momentum, and also conservation of angular momentum, aswell as the conservation of electric charge

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Density is a measure of an object's _____ per unit _____.
ladessa [460]
<span>Density is a measure of an object's </span>mass per unit of volume

Which means that it shows how much mass is contained within a volume of something.
7 0
3 years ago
suppose that a large cargo truck needs to cross a bridge. the truck is 30 m long and 3.2 m wide. the cargo exerts a force nof 54
Tamiku [17]
<span>No, because the truck applies more pressure than the bridge can support.</span>
7 0
3 years ago
What is the kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s?
Oksana_A [137]
Kinetic energy = (1/2) (mass) (speed)²

                         = (1/2) (1.4 kg) (22.5 m/s)²

                         =    (0.7 kg)  (506.25 m²/s² )

                         =          354.375  kg-m²/s²  =  354.375 joules .

This is just the kinetic energy associated with a 1.4-kg glob of
mass sailing through space at 22.5 m/s.  In the case of a frisbee,
it's also spinning, and there's some additional kinetic energy stored
in the spin. 
8 0
3 years ago
8. Three grams of Bismuth-218 decay to 0.375 grams in one hour. What is the half-
Evgen [1.6K]

Answer: 0.333 h

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula</u>:  

A=A_{o}.2^{\frac{-t}{H}} (1)  

Where:  

A=0.375 g is the final amount of the material  

A_{o}=3 g is the initial amount of the material  

t=1 h is the time elapsed  

H is the half life of the material (the quantity we are asked to find)  

Knowing this, let's substitute the values and find h from (1):

0.375 g=(3 g)2^{\frac{-1h}{H}} (2)  

\frac{0.375 g}{3 g}=2^{\frac{-1h}{H}} (3)  

Applying natural logarithm in both sides:

ln(\frac{0.375 g}{3 g})=ln(2^{\frac{-1 h}{H}}) (4)  

-2.079=-\frac{1 h}{H}ln(2) (5)  

Clearing H:

H=\frac{-1h}{-2.079}(0.693) (6)  

Finally:

h=0.333 h This is the half-life of the Bismuth-218 isotope

4 0
4 years ago
A fish scale, consisting of a spring with spring constant k=200N/m, is hung vertically from the ceiling. A 2.6 kg fish is attach
Olegator [25]

Answer:

Explanation:

The fish is initially at rest and it is also at rest when the spring is fully stretched at the maximum distance.

Change in gravity potential energy = change in spring potential energy

mgh = 1/2kh^2

Assume gravity constant g is 10m/s^2

2.6*10*h = 1/2*200*h^2

100h^2 - 26h = 0

2h(50h - 13) = 0

h = 0 or h = 13/50 = 0.65m

h = 0 is before the spring is stretched

So the maximum distance is 0.65m.

3 0
2 years ago
Read 2 more answers
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