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3 years ago

If a space craft that seems to be motionless in deep space is given some type of quick push what will happen?

Physics

1 answer:

podryga [215]3 years ago

7 0

D: the spacecraft will move and will not stop until it is stopped by an equal and opposite force.

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The concentration of a solution refers to the

Setler79 [48]

Answer: It is the ratio of solute in a solution to either solvent or total solution.

Explanation:

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3 years ago

A skydiver of mass 87 kg falls straight down. If air resistance exerts 355 N of force on him as he falls, what is the net force

alukav5142 [94]

Answer:

497.6 N

Explanation:

From the question,

The net force on the skydiver = weight of the skydiver- the resistive force of air

F' = W-F...................... Equation 1

Where W = weight of the skydiver, F = resistive force of air.

But,

W = mg................ Equation 2

Where m = mass of the skydiver, g = acceleration due to gravity.

Substitute equation 2 into equation 1

F' = mg-F............ Equation 3

Given: m = 87 kg, F = 355 N, g = 9.8 m/s²

Substitute these values into equation 3

F' = 87(9.8)-355

F' = 852.6-355

F' = 487.6 N

6 0

3 years ago

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Use what you learned in the passage to

Katyanochek1 [597]

Answer:

Explanation:

Dennis, 60 feet in 0.5 seconds

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3 years ago

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Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electri

Romashka-Z-Leto [24]

The change in surface area of Gaussian surface with radius (r) is 8πr.

<h3>Electric field from Coulomb's law</h3>

The electric field experienced by a charge is calculated as follows;

$E = \frac{Q}{4\pi \varepsilon_o r^2}$

where;

E is the electric field
Q is the charge
r is the radius

The electric field reduces by a factor of $\frac{1}{r^2}$

<h3>Surface area of a Gaussian surface;</h3>

The surface area of a sphere is given as;

$A = 4\pi r^2$

<h3>Change in area with r</h3>

$\frac{dA}{dr} = 8\pi r$

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

Learn more about area of Gaussian surfaces here: brainly.com/question/17060446

7 0

3 years ago

If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 70 km/h . The c

olganol [36]

as it is given that curved marked the speed as v = 70 km/h

so we will first convert the speed into m/s

$v = 70 km/h = 19.44 m/s$

now we know that here friction force will provide centripetal force

$F_c = F_f$

As we know that centripetal force is given as

$F_c = \frac{mv^2}{R}$

$\frac{mv^2}{R} = \mu_k mg$

$\frac{v^2}{R} = \mu_k g$

$v^2 = \mu_k R * g$

$19.44^2 = 0.5* R * 9.8$

$378 = 4.9 * R$

$R = 77.1 m$

3 0

4 years ago

Read 2 more answers