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Leona [35]
3 years ago
5

Large power plants in the United States currently use what generators.

Physics
1 answer:
Natalija [7]3 years ago
3 0
<span>Many power plants in the United States use fossil fuels like natural gas and coal to generate energy, while others use nuclear power. </span>
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If you weighed 130 pounds on earth, you would weigh _____pounds on the moon
Aneli [31]

Answer:

152 pounds

Explanation:

4 0
3 years ago
You exit the Vet's Office.
kifflom [539]

(1) When you exit the office, your position is 60.8 m and the total distance traveled is 60.8 m.

(2) When you walk to the bank, your position is 60.8 m, displacement is 0 and the total distance traveled is 121.6 m.

(3) When you walk to flower shop, your position is 26.9 m, displacement is 0 and the total distance traveled is 148.5 m.

(4) When you walk to the Vet's Office, your position is 60.8 m, displacement is 60.8 m and the total distance traveled is 182.4 m.

<h3>You exit the Vet's Office</h3>

When you exit the Vet's Office, your position is 60.8 m (assuming your starting position is the bank).

The total distance have you travelled = 26.9 m + 33.9 m = 60.8 m

<h3>You walk to the Bank</h3>

your new position is 60.8 m

your displacement = 60.8 m - 60.8 m = 0 (assuming your starting position is the bank)

total distance have you travelled = 60.8 m +  60.8 m = 121.6 m

<h3>You walk to the Flower Shop</h3>

your new position is 26.9 m

your total displacement = 0 + 26.9 m = 26.9 m

total distance have you travelled = 26.9 m + 121.6 m = 148.5 m

<h3>You walk to the Vet's Office</h3>

your new position is 26.9 m + 33.9 m = 60.8 m

your total displacement = 26.9 m + 33.9 m = 60.8 m

total distance have you travelled = 148.5 m + 33.9 m = 182.4 m

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

5 0
2 years ago
Which form of the energy is used to generate electrical energy in a tidal power station
Alla [95]

Tidal energy is the form of energy used to generate electrical energy.

7 0
3 years ago
Why does an object roll faster down a steeper hill than a not so steep hill.
Natasha2012 [34]
 The answer is : <span>Gravity draws an object towards its strongest point. The main things holding you back are air resistance and friction. As a hill gets steeper, you are more in line with the center of gravity, so it overcomes friction and you move faster. Eventually when you are moving vertically there is no friction other than air resistance itself. At this time you will accelerate at 32 feet per second every second until you either hit something or reach terminal velocity which is around 120 mph. Air resistance (on the Earth at least) will not allow you to travel any faster. Hope this Helped! Good Luck! :)</span>
3 0
3 years ago
A world-class sprinter running a 100 m dash was clocked at 5.4 m/s 1.0 s after starting running and at 9.8 m/s 1.5 s later. In w
cupoosta [38]

Answer:

<em>The output power is greater in the interval from 1.0 s to 2.5 s</em>

Explanation:

<u>Physical Power </u>

It measures the amount of work W an object does in certain time t. The formula needed to compute power is

\displaystyle P=\frac{W}{t}

Work can be computed in several ways since we are given the motion conditions, we'll use this formula, for F= applied force, x=distance parallel to F

W=F.x

The second Newton's law gives us the net force as

F=m.a

being m the mass of the object and a the acceleration it has for a given period of time. In our problem, we have two different behaviors for each interval and we must calculate this force since the acceleration is changing. Let's calculate the acceleration in the first interval. We can use the formula for the final speed vf knowing the initial speed vo (which is 0 because the sprinter starts from rest), the acceleration a, and the time t:

v_f=v_o+at

v_f=at

Solving for a

\displaystyle a=\frac{v_f}{t}={5.4}{1}

a=5.4\ m/s^2

The distance traveled in the interval is given by

\displaystyle x=v_o.t+\frac{a.t^2}{2}

Since vo=0

\displaystyle x=\frac{a.t^2}{2}=\frac{5.4(1)^2}{2}

x=2.7\ m

The force is given by

F=m.a

We don't know the value of m, so the force is

F=2.7m

Computing the work done by the sprinter

W=F.x=2.7m(5.4)

W=14.58m

The power is finally computed

\displaystyle P=\frac{W}{t}=\frac{14.58m}{1}

P=14.58m

During the second interval, from t=1 sec to 1.5 sec, the speed changes from 5.4 m/s to 9.8 m/s. This allows us to compute the second acceleration

\displaystyle a=\frac{v_f-v_o}{t}=\frac{9.8-5.4}{0.5}

a=8.8\ m/s^2

The distance is

\displaystyle x=(5.4).(0.5)+\frac{8.8(0.5)^2}{2}

x=3.8\ m

The net force is

F=m(8.8)=8.8m

The work done by the sprinter is now computed as

W=8.8m(3.8)=33.44m

At last, the output power is

\displaystyle P=\frac{33.44m}{0.5}=66.88m

By comparing both results, and being m the same for both parts, we conclude the output power is greater in the interval from 1.0 s to 2.5 s

6 0
4 years ago
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