Answer:
a) E = 6.4 1019 J b) v = 0.69 10⁴4 m / s
Explication
a) convert E = 4.0 eV
1 eV = 1.6 10⁻¹⁹ J
E = 4.0 eV (1.6 10⁻¹⁹ J / 1 eV)
E = 6.4 10⁻¹⁹ J
b) Suppose we have a frontal shock and all the kinetic energy of oxygen is transferred to Cs
Ei = K = ½ m v²
Ef = 6.4 10⁻¹⁹ J
½ m v² = 6.4 10⁻¹⁹
The oxygen mass of the periodic table is
PA = 15,999 u
1u = 1.660 10⁻²⁷ kg
Pa = 15,999 1,660 10⁻²⁷ kg
m= Pa = 26,558 10⁻²⁷ kg
Let's calculate the speed
v2 = 2 / m 6.4 10⁻¹⁹
v2 = 2 / 26,558 10⁻²⁷ 6.4 10⁻¹⁹ =
v = √0.4819 10⁸
v = 0.69 10⁴4 m / s
<span>(a)
Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get:
18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component.
(b)
To much the same end do we derive the vertical component:
18.0*sin37.5 = v_y = 10.96 ms^-1
Which we then divide by acceleration, a_y, to derive the time till maximal displacement,
10.96/9.8 = 1.12 s
Finally, doubling this value should yield the particle's total time with r_y > 0
<span>2.24 s
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30*3*60=5400
300*2=600
1500*3=4500
200*10*60=120000
the computer uses more energy.
(you can multiply all results by 60 to get the energy in J, but it's not necessary for the comparison)
The required increase in temperature is:
Explanation:
When the temperature increases, the area of an object increases according to the equation
where
is the initial area
is the coefficient of linear expansion
is the change in area
is the change in temperature
For the steel ball in this problem, we have:
, so the radius is
Therefore, the surface area is
The coefficient of linear expansion for steel is
And the change in area of the ball is
Therefore, the required increase in temperature is:
Learn more about temperature:
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