All categories

3 years ago

How does the mass affect the speed as it rolls down a slope?

1 answer:

6 0

As we use the Kinetic energy and the equation is 1/2mv^2, changing its mass will change its speed and its energy. So more mass, more speed more energy. also the gravitational potential energy; mass x gravity x height; more mass and more height more speed as it go down to the slope! Hope it helps!

You might be interested in

You stand on a spring scale on the floor of an elevator. Of the following, the scale shows the highest reading when the elevator

Virty [35]

Answer:

move upward with increasing speed

I draw fbd diagram , see in figure

when lift going upward -

F - mg = ma

f = m( a + g)

scale so highest reading

5 0

4 years ago

If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?

steposvetlana [31]

Hi there!

$\large\boxed{\text{B) 20 meters}}$

We know that:

$E_T = U + K$

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

3 0

3 years ago

A car wheel turns through 277° in 10.7 s. Calculate the angular speed of the wheel.

slava [35]

Answer:

The angular speed of the wheel is 0.452 rad/s

Explanation:

The angle through which the car wheel turns, Δθ = 277° = 277/360 × 2·π radian

The time it takes for the car wheel to turn, Δt = 10.7 s

The angular speed, ω is given by the following equation;

$Angular \ speed = \dfrac{Change \ in \ angular \ rotation }{Change \ in \ time} = \dfrac{\Delta \theta}{\Delta t}$

Substituting the known values for Δθ and Δt gives;

$Angular \ speed = \dfrac{\dfrac{277 ^{\circ}}{360 ^{\circ } } \times 2 \times \pi \ radian}{10.7 \ seconds} \approx 0.452 \ rad/s$

The angular speed of the wheel = 0.452 rad/s

3 0

3 years ago

Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t

Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

$g=\frac{GM}{R^2}=9.70 m/s^2$

where G is the gravitational constant

M is the Earth's mass

$R=6378km = 6.378 \cdot 10^6 m$ is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

$M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg$

The Earth's volume is (approximating the Earth to a perfect sphere)

$V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3$

So, the average density of the Earth is

$\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3$

4 0

4 years ago

Read 2 more answers

If you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out. This happens

amm1812

Answer:

True

Explanation:

If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.

<u>Centrifugal force is mathematically related as:</u>

$F=m.r.\omega^2$

where:

m = mass of the revolving body

r = radius of revolution

$\omega=$ angular velocity in radians per second

This force F acts in radially outward direction.

3 0

4 years ago