Answer: the correct answer is 7.8026035971 x 10^(-13) joule
Explanation:
Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get
m = 4.00260 u + 222.01757 u = 226.02017 u .
The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is
Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,
which is equivalent to an energy change of
Delta E = (0.00523 u)*(931.5MeV/1u)
Delta E = 4.87 MeV
Converting 4.87 MeV to Joules
1 joule [J] = 6241506363094 mega-electrón voltio [MeV]
4 mega-electrón voltio = 6.40870932 x 10^(-13) joule
4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule
The average speed is determined by the following formula:
average speed = [sum of (speed * time for which that speed was traveled)] / total time
average speed = [(83 * 26 + 41 * 52 + 60 * 45 + 0 * 15) / 60] / [(26 + 52 + 45 + 15) / 60]
*note: The division by 60 is to convert minutes to hours. We see that the 60 cancels from the top and bottom of the division
average speed = 50.65 km/hr
The total distance traveled is equivalent to the numerator of the fraction we used in the first part. This is:
Distance = (83 * 26 + 41 * 52 + 60 * 45 + 0 * 15) / 60
Distance = 116.5 kilometers
D. Because the moons shadow during a total lunar eclipse is tinnier than the earth.
Answer:
(a) 0.075
(b)20.1 mA
(c) 2.412 W
Explanation:
Vs = 9 V, is = 268 mA = 0.268 A
Vp = 120 V
(a) Let the number of turns in primary coil is Np and the number of turns in secondary coil of the transformer is Ns.
Ns / np = Vs / Vp
Ns / Np = 9 / 120
Ns / Np = 3 : 40 = 0.075
(b) Let the current drawn from the wall socket is ip.
Ns/ Np = ip / is
0.075 = ip / 0.268
ip = 0.0201 A = 20.1 mA
(c) Power delivered by the socket = Vp x ip = 120 x 0.0201 = 2.412 W
Power sent to the batteries = Vs x is = 9 x 0.268 = 2.412 W
