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4 years ago

Why do all the electrons in an iron atom not settle together into the lowest energy state? because.?

1 answer:

3 0

Electrons in an iron atom (or in any atom) cannot settle all together into the lowest energy state because of Pauli exclusion principle: this principle states that two or more identical fermions (and so, electrons included) cannot occupy the same quantum state of a system at the same time.

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is the following sentence true or false? the faster the particles of a substance are moving, the more energy they have.

svetlana [45]

I think true. I'm pretty sure, but check w/ others too.

8 0

3 years ago

Read 2 more answers

A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between

Sunny_sXe [5.5K]

Answer : $4.483\times 10^{15}\ m/s^2$ .

Explanation:

It is given that,

Electric field strength, $E=2.55\times 10^{4}\ N/C$

We know that,

Charge of electron, $q=1.6\times 10^{-19}\ C$

Mass of electron, $m=9.1\times 10^{-31}\ kg$

From the definition of electric field, $F=qE$ ...............(1)

According to Newton's second law, F = ma..........(2)

From equation (1) and (2)

$ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\ C\times 2.55\times 10^{4}\ N/C }{9.1\times 10^{-31}\ kg}$

$a=0.4483\times 10^{16}\ m/s^2$

$a=4.483\times 10^{15}\ m/s^2$

So, the horizontal component of acceleration of an electron is $4.483\times 10^{15}\ m/s^2$ .

Hence, it is the required solution.

7 0

3 years ago

7. How much work is done in moving a charge of 10 micro coulombs 1 meter along an equipotential of 10 volts?

Neko [114]

It takes work to push charge through a change of potential.
There's no change of potential along an equipotential path,
so that path doesn't require any work.

8 0

3 years ago

Read 2 more answers

An irregular shape object has a mass of 19 oz. A graduated cylinder with and initial volume of 33.9 mL. After the object was dro

madreJ [45]

Explanation:

m = 19 oz × (28.3 g/1 oz) = 537.7 g

V = 92.8 mL

$\rho = \dfrac{m}{V}= \dfrac{537.7\:g}{92.8\:mL} = 5.79\:\frac{g}{mL}$

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3 years ago

two blocks are held together with a compressed spring between them on the surface of a slippery table .one block has three times

Marina CMI [18]

Explanation:

The initial kinetic energy $KE_0$ for both blocks is zero. Let $m_1= m$ and $m_2 =3m$ . So using the conservation law of linear momentum, we can write