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JulsSmile [24]
3 years ago
12

Two forces 5N and 10N are acting at "O" and "P" respectively on a uniform rod of length 100 cm suspended at the position of cent

er of gravity 50cm mark as shown in figure .​

Physics
1 answer:
omeli [17]3 years ago
5 0

Answer:

Option C. 75 cm

Explanation:

To obtain the position of P, let us calculate the value of y as shown in the attached photo.

The value of y can be obtained as follow:

Anticlockwise moment = clockwise moment

Anticlockwise moment = 5 × 50

Anticlockwise moment = 250

Clockwise moment = y × 10

Anticlockwise moment = clockwise moment

250 = y × 10

Divide both side by 10

y = 250/10

y = 25 cm

Finally, we shall obtain the value of P as follow:

Since P lies after the pivot (i.e 50 cm), therefore,

P = 50 + y

y = 25

P = 50 + 25

P = 75 cm

Therefore, the position of P on the metre rod is 75 cm

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A pirate ship shoots a cannon towards an oncoming ship. The cannon ball has a mass of 25 kg and the ship has a mass of 2500 kg.
mars1129 [50]

Answer:

25 m/s in the opposite direction with the ship recoil velocity.

Explanation:

Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

m_sv_s + m_bv_b = 0

where m_s = 2500 kg, m_b = 25 kg are masses of the ship and ball respectively. v_s = 0.25 m/s, v_b are the velocities of the ship and ball respectively, after the shooting.

2500*0.25 + 25*v_b = 0

25v_b = -2500*0.25

v_b = -2500*0.25/25 = -25 m/s

So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.

3 0
3 years ago
Light in vacuum travels at a speed of 3.00 x 10^8 m ^-1 s^-1 on average earth is 93,000,000 miles from the sun how many minutes
NemiM [27]
The correct unit for the speed of light is  [ m s⁻¹ ].

Time = (distance) / (speed)

Time = (9.3 x 10^7 miles) x (1609 m/mile) / (3 x 10^8 m/s) = 498.8 seconds .

That would be  <em>8.31 minutes</em>.  
6 0
3 years ago
What is the likely identity of a metal if a sample has a mass of 63.5 g when measured in air and an apparent mass of 60.2 g when
Gre4nikov [31]

Answer:

Gold

Explanation:

Given:

Mass of sample = 63.5 g

Mass of water = 60.2 g

Find:

Object

Computation:

Mass of water displaced = 63.5 g - 60.2 g

Mass of water displaced = 3.3 g

So, volume in water = 3.3 cm³

Density = Mass / Volume

Density = 63.5 g / 3.3

Density = 19.24

So,

Object ,must be gold.

7 0
2 years ago
An electron is released a short distance above earth's surface. a second electron directly below it exerts an electrostatic forc
slamgirl [31]

The mass of an electron is 9.109 x 10⁻³¹ kg

The weight of the electron is (mass) x (g) =  8.926 x 10⁻³⁰ Newton

The charge on an electron is -1.602 x 10⁻¹⁹ Coulomb

The repelling force between the two electrons is (K · q₁ · q₂ / r²) =

(8.98755 x 10⁹ N-m²/C²) x (1.602 x 10⁻¹⁹ C)² / D²

In order for the bottom one to just exactly hold the top one up at a distance 'D', the repelling force has to be exactly equal to the weight of the upper electron.

8.926 x 10⁻³⁰ N = (8.98755 x 10⁹ N-m²/C²)·(1.602 x 10⁻¹⁹ C)² / D²

We have to solve THAT ugly mess for ' D '.

Clean up the units first:

Cancel the C² on the right side, then divide each side by Newton:

8.926 x 10⁻³⁰ = (8.98755 x 10⁹ m²) x (1.602 x 10⁻¹⁹)² / D²

Now, let's multiply both sides by (D² x 10²⁹) :

D² x 8.926 x 10⁻¹ = (8.98755 m²) x (1.602)²

Divide each side by (0.8926):

D² = (8.98755 x 1.602²) / (0.8926)  meter²

D² = 25.84 m²

Take the square root of each side:

<em>D = 5.08 meters</em>

I am shocked, impressed, and amazed !

Are you shocked, impressed, or amazed ?

3 0
4 years ago
You are measuring the mass of different chemicals to get ready to conduct an experiment.
vova2212 [387]

Answer:

B) grams

The SI unit for mass is grams.

3 0
3 years ago
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