Answer:
V₀ₓ = 10.94 m/s
V₀y = 18.87 m/s
Explanation:
To find the launch velocity, we use 1st equation of motion.
Vf = Vi + at
where,
Vf = Final Velocity of Ball = Launch Speed = V₀ = ?
Vi = Initial Velocity = 0 m/s (Since ball was initially at rest)
a = acceleration = 376 m/s²
t = time = 0.058 s
Therefore,
V₀ = 0 m/s + (376 m/s²)(0.058 s)
V₀ = 21.81 m/s
Now, for x-component:
V₀ₓ = V₀ Cos θ
where,
V₀ₓ = x-component of launch velocity = ?
θ = Angle with horizontal = 59.9⁰
V₀ₓ = (21.81 m/s)(Cos 59.9°)
<u>V₀ₓ = 10.94 m/s</u>
<u></u>
for y-component:
V₀ₓ = V₀ Sin θ
where,
V₀y = y-component of launch velocity = ?
θ = Angle with horizontal = 59.9⁰
V₀y = (21.81 m/s)(Sin 59.9°)
<u>V₀y = 18.87 m/s</u>
<u></u>
Answer:
The relative velocity of the motorcycle to a passenger in the car is 30 km/h
Explanation:
The question relates to the principle of relative velocity and reference frames
The given parameters are;
The velocity of the motorcycle, v₁ = 120 km/h
The velocity of the car, v₂ = 90 km/h
The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as 
= 
- 
Therefore, the relative velocity of the motorcycle to the car is 
= v₁ - v₂, which give;
= 120 km/h - 90 km/h = 30 km/h
The relative velocity of the motorcycle to a passenger in the car = 30 km/h.
Answer:
Sound and light are similar in that both are forms of energy that travel in waves.
Explanation:
They both have properties of wavelength, freqency and amplitude. ... Sound can only travel through a medium (substance) while light can travel through empty space. Sound is a form of mechanical energy caused by vibrations of matter.
When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
To find the answer, we have to know about the rules followed by drawing ray-diagram.
<h3>What are the rules obeyed by light rays?</h3>
- If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
- The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
- The refracted ray follows the same path if the incident light passes through the center of the curve.
Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
Learn more about refraction by a lens here:
brainly.com/question/13095658
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