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snow_lady [41]
3 years ago
11

Aniel Bowen borrowed $10,000 for 3 years at 13% rate of interest. Find the simple interest.

Mathematics
1 answer:
Oksana_A [137]3 years ago
4 0

Answer:

fylinh rhthkrjehtegjhgjebjbebkbkbkertgbgrbkrt

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Write the first five terms of the arithmetic sequence. a4 = 22, a10 = 64
dedylja [7]
Hello :
the general term is : 
an = a1+(n-1)×d  
or : an = ap +(n-p)×d......d is common diffrence
let : n=10 and p= 4
a10 =  a4 +(10-4)×d
64 = 22 + 6d
6d =  42
d= 7
conclusion :
a4 = 22
a3 = 22-7=15
a2=15-7=8
a1= 8-7=1
<span>the first five terms : 1 , 8 , 15 , 22</span>

4 0
2 years ago
Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0
choli [55]
Hello,
center is (4,-6)
radius=4
since
x^2-8x+y^2+12y+36=0\\&#10;&#10;x^2-2*4x+16-16+y^2+2*6y+36=0\\&#10;&#10;(x-4)^2+(y+6)^2=4^2&#10;&#10;


3 0
3 years ago
Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x &gt; 0 and y &gt; 0.
morpeh [17]
The first step for solving this expression is to reduce the fraction with 11.
\sqrt{ \frac{5 x^{7} y^{6}  }{ x^{11}  y^{8} } }
Now reduce the fraction with x^{7}.
\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8}  } }
Reduce the fraction one more time with y^{6}.
\sqrt{ \frac{5}{ x^{4} y^{2}  } }
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
\frac{ \sqrt{5} }{ x^{2} y}
Since we cannot simplify this fraction any further,, the final answer is going to be \frac{ \sqrt{5} }{ x^{2} y}.
Let me know if you have any further questions.
:)
3 0
3 years ago
Read 2 more answers
Quadratics formula 4x^2+3x-1=0
VARVARA [1.3K]

Answer: X = 1/4 or X = -1

Step-by-step explanation:

4x2+3x−1=0

(4x−1)(x+1)=0

4x−1=0 or x+1=0

4x=1 or x=-1

Now divide 4 from both sides

like this 4x/4=1/4

now cancel out two 4's so the answer will be x=1/4

3 0
3 years ago
What would the correct answer be???
tiny-mole [99]

Answer:

8.27837797

I think this is correct im not completely sure.

8 0
3 years ago
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