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3 years ago

Exceeding critical mach may result in the onset of compressibility effects such as:______.

Engineering

1 answer:

klio [65]3 years ago

4 0

Answer:

Sound barrier.

Explanation:

Sound barrier is a sudden increase in drag and other effects when an aircraft travels faster than the speed of sound. Other undesirable effects are experienced in the transonic stage, such as relative air movement creating disruptive shock waves and turbulence. One of the adverse effect of this sound barrier in early plane designs was that at this speed, the weight of the engine required to power the aircraft would be too large for the aircraft to carry. Modern planes have designs that now combat most of these undesirable effects of the sound barrier.

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mars1129 [50]

Answer and explanation:

The graphical representation of the electronic eye

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3 years ago

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sdas [7]

Neither of the two technicians (Technician A and Technician B) is correct.

<h3>What is an engine vacuum?</h3>

An engine vacuum can be defined as a type of engine which is designed and developed to derive its force from air pressure that's being pushed against one side of the piston of an automobile, while having a partial vacuum on the other side.

In this scenario, we can infer and logically conclude that neither of the two technicians (Technician A and Technician B) is correct because engine vacuum is high when the engine is operating under light loads and vice-versa.

Read more on engine vacuum here: brainly.com/question/14602340

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2 years ago

What are the two reasons for a clear cut

Inessa [10]

Answer:

to clear land for agriculture and settlement and to use or sell timber for lumber, paper products, or fuel.

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3 years ago

If a 9V battery produces a current of 3 A through a load, what is the resistance of the load

Elden [556K]

3 ohms hope this helps :D ❤

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2 years ago

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A race car is travelling around a circular track. The velocity of the car is 20 m/s, the radius of the track is 300 m, and the m

Zielflug [23.3K]

Answer:

μ = 0.136

Explanation:

given,

velocity of the car = 20 m/s

radius of the track = 300 m

mass of the car = 2000 kg

centrifugal force

$F_c = \dfrac{mv^2}{r}$

$F_c = \dfrac{2000\times 20^2}{300}$

F c = 2666. 67 N

F f= μ N

F f = μ m g

2666.67 = μ × 2000 × 9.8

μ = 0.136

so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136

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3 years ago