Answer:
9500 kJ; 9000 Btu
Explanation:
Data:
m = 100 lb
T₁ = 25 °C
T₂ = 75 °C
Calculations:
1. Energy in kilojoules
ΔT = 75 °C - 25 °C = 50 °C = 50 K
![m = \text{100 lb} \times \dfrac{\text{1 kg}}{\text{2.205 lb}} \times \dfrac{\text{1000 g}}{\text{1 kg}}= 4.54 \times 10^{4}\text{ g}\\\\\begin{array}{rcl}q & = & mC_{\text{p}}\Delta T\\& = & 4.54 \times 10^{4}\text{ g} \times 4.18 \text{ J$\cdot$K$^{-1}$g$^{-1}$} \times 50 \text{ K}\\ & = & 9.5 \times 10^{6}\text{ J}\\ & = & \textbf{9500 kJ}\\\end{array}](https://tex.z-dn.net/?f=m%20%3D%20%5Ctext%7B100%20lb%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20kg%7D%7D%7B%5Ctext%7B2.205%20lb%7D%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1000%20g%7D%7D%7B%5Ctext%7B1%20kg%7D%7D%3D%204.54%20%5Ctimes%2010%5E%7B4%7D%5Ctext%7B%20g%7D%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Brcl%7Dq%20%26%20%3D%20%26%20mC_%7B%5Ctext%7Bp%7D%7D%5CDelta%20T%5C%5C%26%20%3D%20%26%204.54%20%5Ctimes%2010%5E%7B4%7D%5Ctext%7B%20g%7D%20%5Ctimes%204.18%20%5Ctext%7B%20J%24%5Ccdot%24K%24%5E%7B-1%7D%24g%24%5E%7B-1%7D%24%7D%20%5Ctimes%2050%20%5Ctext%7B%20K%7D%5C%5C%20%26%20%3D%20%26%209.5%20%5Ctimes%2010%5E%7B6%7D%5Ctext%7B%20J%7D%5C%5C%20%26%20%3D%20%26%20%5Ctextbf%7B9500%20kJ%7D%5C%5C%5Cend%7Barray%7D)
2. Energy in British thermal units
![\text{Energy} = \text{9500 kJ} \times \dfrac{\text{1 Btu}}{\text{1.055 kJ}} = \text{9000 Btu}](https://tex.z-dn.net/?f=%5Ctext%7BEnergy%7D%20%3D%20%5Ctext%7B9500%20kJ%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20Btu%7D%7D%7B%5Ctext%7B1.055%20kJ%7D%7D%20%3D%20%5Ctext%7B9000%20Btu%7D)
Hi
Acetylene and propane
I hope this help you!
Answer:
The rate of heat generation in the wire per unit volume is 5.79×10^7 Btu/hrft^3
Heat flux is 9.67×10^7 Btu/hrft^2
Explanation:
Rate of heat generation = 1000 W = 1000/0.29307 = 3412.15 Btu/hr
Area (A) = πD^2/4
Diameter (D) = 0.08 inches = 0.08 in × 3.2808 ft/39.37 in = 0.0067 ft
A = 3.142×0.0067^2/4 = 3.53×10^-5 ft^2
Volume (V) = A × Length
L = 20 inches = 20 in × 3.2808 ft/39.37 in = 1.67 ft
V = 3.53×10^-5 × 1.67 = 5.8951×10^-5 ft^3
Rate of heat generation in the wire per unit volume = 3412.15 Btu/hr ÷ 5.8951×10^-5 ft^3 = 5.79×10^7 Btu/hrft^3
Heat flux = 3412.15 Btu/hr ÷ 3.53×10^-5 ft^2 = 9.67×10^7 Btu/hrft^2
Answer:
The correct answer is
option C. current to pneumatic (V/P)
Explanation:
A current to pneumatic controller is basically used to receive an electronic signal from a controller and converts it further into a standard pneumatic output signal which is further used to operate a positioner or control valve. These devices are reliable, robust and accurate.
Though Voltage and current to pressure transducers are collectively called as electro pneumatic tranducers and the only electronic feature to control output pressure in them is the coil.
The correct statement is: a higher than a normal voltage drop could indicate high resistance. Technician B is correct.
<h3>Ohm's law</h3>
Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical conditions are constant. Mathematically, it is expressed as
V = IR
Where
V is the potential difference
I is the current
R is the resistance
<h3>Technician A</h3>
High resistance causes an increase in current flow
V = IR
Divide both side by I
R = V / I
Thus, technician A is wrong as high resistance suggest low current flow
<h3>Technician B</h3>
Higher than normal voltage drop could indicate high resistance
V = IR
Thus, technician B is correct as high voltage indicates high resistance
<h3>Conclusion </h3>
From the above illustration, we can see that technician B is correct
Learn more about Ohm's law:
brainly.com/question/796939