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3 years ago

PLEASE HELP ANSWER THIS. (a) Which two conditions must be fulfilled by balanced ionic equations? select all that apply

Chemistry

1 answer:

SCORPION-xisa [38]3 years ago

7 0

Answer:

Explanation:

The first two answers are the correct ones. Sometimes C can be true, but it is not a condition. Some equations produce many more products than reactants and some equations are made from more reactants than products.

The last one is normally not true, but the three equations I choose below do give D to be true. Still it does not happen all the time.

C8H18 + 12.5 O2 ===> 8CO2 + 9H20 This is the combustion equation that drives your engine. The coefficients do not add.

Same number of reactants as products.

CH4 + 2O2 ==> CO2 + 2H2O

More products than reactants.

Cu + 4HNO3 ==> Cu(NO3)2 + 2NO2 + 2H2O

More Reactants than products.

H2 + I2 ==> 2HI

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A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

Elan Coil [88]

Answer:

a. Moles of $NaOH$ = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $NaOH$ :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of $NaOH$ :

$Moles=0.1052 \times {15.62\times 10^{-3}}\ moles$

Moles of $NaOH$ = 0.001643 moles

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains $\frac{0.296}{1.159}\times 1.213$ g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

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Answer:

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