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valentinak56 [21]
3 years ago
12

What is E=m² the famous theory of albert einstien?

Physics
2 answers:
ELEN [110]3 years ago
5 0
Theory of relativity and E = mc²

Main article: History of special relativityEinstein's "Zur Elektrodynamik bewegter Körper" ("On the Electrodynamics of Moving Bodies") was received on 30 June 1905 and published 26 September of that same year. It reconciles Maxwell's equations for electricity and magnetism with the laws of mechanics, by introducing major changes to mechanics close to the speed of light. This later became known as Einstein's special theory of relativity.
pshichka [43]3 years ago
3 0
Actually it's E = mc^{2} and it says that the energy of an object (E) is equal to the mass (m) of the object multiplied with the squared speed of light (c^{2}). This theory says that mass can be turned into energy and energy can be turned into mass. This is one of Einstein's theory of relativity.
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Quantum mechanics can be thought of as a ...
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c. probablistic view of nature.

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Which of the following is neutral?
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Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin,
Elza [17]

The electric field is zero at x = -16.45cm

Data;

  • q1 = 3.4 μC
  • q2 = -2.0 μC
  • distance = 5cm

<h3>The Electric Field at point 0</h3>

As the 3μC is larger than -2.0μC  and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\

Let's solve for x using mathematical methods.

\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0

Solving the above quadratic equation;

x = -16.45cm

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

brainly.com/question/1592046

brainly.com/question/14372859

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