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Nat2105 [25]
2 years ago
10

What is angular velocity

Physics
1 answer:
butalik [34]2 years ago
7 0

Answer:

angular velocity(ω) is the rate change of angular displacement.

ω=θ/t and it SI unit is rad/s

Explanation:

this is very similar with the definition of linear velocity (rate of change of displacement). it specifies the angular speed of an object and the axis about which the object is rotating.

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Effectus [21]

Answer:

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Explanation:

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There is a reflection at the boundary between two materials if there is a change of __________ at the boundary.
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<span>The speed of the light in the materials. Hope this helps!!</span>
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A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec
juin [17]

Answer:

Explanation:

Given that:

angular frequency = 11.3 rad/s

Spring constant (k) = = \omega^2  \times m

k = (11.3)² m

k = 127.7 m

where;

x_1 = 0.065 m

x_2  = 0.048 m

According to the conservation of energies;

E_1=E_2

∴

\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2

kx_1^2 = mv_2^2 + kx_2^2

(127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2

0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325  - 0.2942208 = v_2^2 \\ \\  v_2^2 = 0.2453117 \\ \\  v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}

4 0
3 years ago
A water discharge of 9 m3/s is to flow through this horizontal pipe, which is 0.98 m in diameter. If the head loss is given as 1
Mashutka [201]

Answer: The power required by the pump to produce a discharge of 9m³/s is 5990joules/secs.

Explanation: The given parameters from the questions are:

Flow rate Q = 9m³/s, Diameter D = 0.98m, acceleration a = 1.0, head loss(Pressure P) is given by the function 10v²/2g.

STEP 1. Find the velocity of water in the pipe from the equation:

Diameter D = (√4.Q/π.v), where v is the velocity, and Q is flow rate

Making v subject of the formula gives:

v = 4Q/π.√D =[ 4 × 9m³/s / 3.142 × (√0.98m)] = 11.69m/s.

STEP 2. Find the pressure from the relationship, P = 10v²/2g, NB. g = a

P = 10 × (11.69m/s)² / 2× 1.0m/s²

P = 683.25N/m² or Pascal.

STEP 3. Find force exerted by the pump;

Recall that Pressure P = Force/Area

But Area A = π.r², where r = D/2

Therefore, A = π.(D/2)²

A = 3.142 × [0.98m/2]² = 0.75m²

Therefore, Force = Pressure × Area

Force F = 683.25N/m² × 0.75m²

F = 512.44N.

STEP 4. Find work done

Work done W by the pump is = Force × distance d moved by the water

W = F . d

Also recall that flow rate Q = Velocity/time.

Q = v/t, we can write t = v/Q.

Time t = 11.69m/s / 9m³/s = 1.298s

Also recall that velocity v = distance d/time t, v = d/t, making d subject of formula gives v × t

Distance d = v × t = 11.69m/s × 1.298s = 15.17m.

Hence,

Work Done W = Force × distance

W = 512.44N × 15.17m = 7775.56Nm or joules.

Lastly, Power P = Work done/ time

P = 7775.56joules/1.298s

P = 5990.4joules/s.

8 0
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How the movement of the earth cause the appeared daily and annual movement of the sun and stars​
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Hope this helps!
7 0
3 years ago
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