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Arlecino [84]
3 years ago
14

15 POINTS!

Physics
2 answers:
photoshop1234 [79]3 years ago
8 0
The first law of inertia says that an object’s speed will not change unless something makes it change.


Newton's First Law of Motion

Place the hard boiled egg on its side and spin it. Put your finger on it gently while it is still spinning in order to stop it. Remove your finger when it stops.

Place the raw egg on its side and spin it. Place your finger gently on the egg until it stops. Once you remove your finger, the egg should start to spin again. The liquid inside the egg has not stopped so it will continue to spin until enough force is applied.


The second law: the strength of the force equals the mass of the object times the resulting acceleration.

Newton's Second Law of Motion

Drop a rock or marble and a wadded-up piece of paper at the same time. They fall at the same rate of speed, but the rock's mass is greater so it hits with greater force.


Finally, the third law says that for every action there is a reaction. 

Newton's Third Law of Motion

Pull one ball or swing back and let it go.

It will swing into the other balls making the ball at the other end swing.

adelina 88 [10]3 years ago
6 0
1. The Egg Drop.

2. The Car down a ramp.

3. Maybe an Airplane race with things on it.
You might be interested in
Three charges, q1 = +2.06 x 10-9 C, q2 = -3.27 x 10-9 C, and q3 = +1.05 x 10-9 C, are located on the x-axis at x1 = 0, x2 = 10.0
lisov135 [29]

Answer:

The resultant force on charge 3 is Fr= -2,11665 * 10^(-7)

Explanation:

Step 1: First place the three charges along a horizontal axis. The first positive charge will be at point x=0, the second negative charge at point x=10 and the third positive charge at point x=20. Everything is indicated in the attached graph.

Step 2: I must calculate the magnitude of the forces acting on the third charge.

F13: Force exerted by charge 1 on charge 3.

F23: Force exerted by charge 2 on charge 3.

K: Constant of Coulomb's law.

d13: distance from charge 1 to charge 3.

d23: distance from charge 2 to charge 3

Fr: Resulting force.

q1=+2.06 x 10-9 C

q2= -3.27 x 10-9 C

q3= +1.05 x 10-9 C

K=9-10^9 N-m^2/C^2

d13= 0,20 m

d23= 0,10 m

F13= K * (q1 * q3)/(d13)^2

F13=9,7335*10^(-8) N

F23=K * (q2 * q3)/(d23)^2

F23= -3,09 * 10^(-7)

Step 3: We calculate the resultant force on charge 3.

Fr=F13+F23= -2,11665 * 10^(-7)

3 0
2 years ago
An object of mass m is traveling in a circle with centripetal force f c. If the velocity of the object is v, what is the radius
Gnom [1K]

Answer:

r = mv^2/ Fc

Explanation:

Got it right

7 0
2 years ago
A rock is dropped from the top of a tower. When it is 40 meters above the ground velocity of 17 m/s. When its velocity is 24 m/s
eimsori [14]

Answer:

Option B is the correct answer.

Explanation:

Let us consider 40 meter above ground as origin.

Initial velocity = 17 m/s

Final velocity = 24 m/s

Acceleration = 9.81 m/s

We have equation of motion v² = u² + 2as

Substituting

         24² = 17² + 2 x 9.81 x s

           s = 14.63 m

Distance traveled by rock = 14.63 m down.

Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m

Option B is the correct answer.

4 0
3 years ago
Question 2 (5 points)
Harlamova29_29 [7]

Answer:

Fossil fuels store energy from the sun as

8 0
3 years ago
Read 2 more answers
Two objects, A with charge +Q and B with charge +4Q, are separated by a distance r. The magnitude of the force exerted on the se
scZoUnD [109]

Answer:

The magnitude of electric force on object B due to object A when they are 2r distance apart is F/4.

Explanation:

Given :

Electric charge on object A = +Q

Electric charge on object B = +4Q

When the objects A and B are r distance apart, the magnitude of electrostatic force exerted on B due to A is given by the relation :

F=\frac{1}{4\pi\epsilon_{0}  } \frac{Q\times4Q}{r^{2} }      .....(1)

Now, the two objects are apart by distance of 2r, hence the force acting on the object B due to A is :

F_{1} =\frac{1}{4\pi\epsilon_{0}  } \frac{Q\times4Q}{(2r)^{2} }

F_{1} =\frac{1}{4\pi\epsilon_{0}  } \frac{Q\times4Q}{4r^{2} }

Substitute equation (1) in the above equation.

F_{1} =\frac{F}{4}

6 0
3 years ago
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