by an echo meter
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#Genius kudi
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.
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Answer:
a) 378Ns
b) 477.27N
Explanation:
Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula
I = Ft = m(v-u)
m is the mass = 70kg
v is the final velocity = 5.4m/s
u is the initial velocity = 0m/s
Get the impulse
I = m(v-u)
I = 70(5.4-0)
I = 70(5.4)
I = 378Ns
b) Average total force is expressed as
F = ma (Newton's second law)
F = m(v-u)/t
F = 378/0.792
F = 477.27N
Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N
Your potential energy and mass don't tell what your weight is.
If I walk up from the first floor to the second floor, my weight hasn't
changed even though my potential energy has increased.
Answer:
It is 52° below the celestial equator.
Explanation:
The declination is the angle in degrees measured north (+) or south (-) of the an imaginary line called the celestial equator.
The celestial equator is a projection of the earth's equator on the celestial sphere. imaginary
The star named Canopus has a declination of approximately –52°.
Since the angle is negative, this shows that it is south or below the celestial equator and at 52° south of the celestial equator.
Thus, the star named Caponus is 52° below the celestial equator.
