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suter [353]
3 years ago
15

If the potential across two parallel plates, separated by 4.0 cm, is 15.0 V, what is the electric field strength in volts per me

ter?
Physics
2 answers:
givi [52]3 years ago
6 0

Answer:

sorry i press 1 star but he's right 375

Explanation:

abruzzese [7]3 years ago
3 0

Field strength = (15 V) / (4 cm)

Field strength = (15 V) / (0.04 meter)

Field strength = (15/0.04) (volts/meter)

<em>Field strength = 375 volts/meter </em>

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A ball is thro.d hit the grouvelocity)?
kati45 [8]

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of  height 61.9 m. So that the velocity can be determined by;

      u = \sqrt{\frac{2H}{g} }

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/s^{2}, then;

 u = \sqrt{\frac{2*61.9}{10} }

   = \sqrt{\frac{123.8}{10} }

u  = 3.5185

The velocity of the ball is 3.52 m/s.

3 0
3 years ago
A teacher performing demonstration finds that a piece of cork displaces 23.5 ml of water. The piece of cork has a mass 5.7 g. Wh
Sedbober [7]

Answer: 0.24g/ml

Explanation:

Given that:

Volume of water displaced = 23.5 ml

Mass of cork = 5.7 g

Density of the cork = ?

Recall that density is obtained by dividing the mass of a substance by the volume of water displaced.

i.e Density = Mass/volume

Density = 5.7g /23.5ml

Density = 0.24g/ml

Thus, the density of the piece of cork is 0.24g/ml

8 0
3 years ago
calculate the work done by 2N force directed at 30 degree to the vertical to move a 500g box a horizontal distance of 400 cm acr
sattari [20]

Answer:

there is no picture :o?

Explanation:

:oo

3 0
2 years ago
A skier moving at 4.75 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220
disa [49]
First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force, \mu m g. For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
ma=-\mu m g
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
a=-(0.220)(9.81 m/s^2)=-2.16 m/s^2

Now we can use the following relationship to find the distance covered by the skier before stopping, S:
2aS=v_f^2-v_i^2
where v_f=0 is the final speed of the skier and v_i=4.75 m/s is the initial speed. Substituting numbers, we find:
S=- \frac{v_i^2}{2a}=- \frac{(4.75 m/s)^2}{2(-2.16 m/s^2)}=5.23 m
5 0
3 years ago
Where does current flows maximum in? series connection or parallel connection?
notsponge [240]
Current flow depends on other things in addition to the circuit configuration. If the SAME voltage is applied to some arrangement of the SAME components, the greatest current will occur when they are all in parallel.
3 0
3 years ago
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