Two opposite forces generate a force whose magnitude is the difference of the two magnitudes, and whose direction is the same of the strongest one.
We have 3320 newtons forward, and 550 backwards.
So, the net force is forward, and has magnitude
A spring scale has a spring with a force constant of 250 N/m and a weighing pan with a mass of 0.075 kg. During one weighing, th
1 answer:
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Answer:
torque is 1.7 * Nm
Explanation:
Given data
turns n = 1000 turns
radius r = 12 cm
current I = 15A
magnitude B = 5.8 x 10^-5 T
angle θ = 25°
to find out
the torque on the loop
solution
we know that torque on the loop is
torque = N* I* A*B* sinθ
here area A = πr² = π(0.12)²
put all value
torque = N* I* A*B* sinθ
torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin25
torque = 0.0166 N m
torque is 1.7 * Nm
Answer: 0.192 N/m
Explanation:
Well, generally when a Hooke's Law experiment is performed the plot is in fact Force vs Displacement, being the Force (in units of Newtons) in the Y-axis and the Displacement (in units of meters) in the X-axis.
In addition, if we add a linear fit the resultant equation will be the Line equation of the form:
Where is the slope and
is the point where the line intersects the Y-axis.
So, if the equation is:
The slope of this line is which is also the spring constant
.