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Strike441 [17]
2 years ago
8

A spring scale has a spring with a force constant of 250 N/m and a weighing pan with a mass of 0.075 kg. During one weighing, th

e spring is stretched a distance of 12 cm from equilibrium. During a second weighing, the spring is stretched a distance of 18 cm.
9. How much greater is the elastic potential energy of the stretched spring during the second weighing than during the first weighing?
Physics
1 answer:
mr Goodwill [35]2 years ago
8 0

elasticity stretches and can also return to it's normal size ..

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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here : 750 J electrical energy i
Charra [1.4K]

Electrical energy is used to run the fan

Here as per given condition 750 J of electrical energy is used to run the fan which is converted into Kinetic energy as 400 J

So here we can see that 350 J of energy is lost against many other type of frictional and resistive loses.

So here we can say that out of 750 J of energy only 400 J is used to run the fan and rest amount of energy is lost against friction.

also we can say that efficiency of this fan will be

\eta = \frac{Useful}{Total}

\eta = \frac{400}{750}

\eta = \frac{8}{25}


3 0
2 years ago
8. Main Idea How do animals reproduce?
Gnoma [55]

Answer: Many multicellular animals like fishes, mammals, birds, etc. reproduce through sexual reproduction process. Even reproduction in domestic animals also occurs through the sexual process. Domestic animals (pets or farm animals) are an essential part of our life. MARK AS BRAINLIST PLZ

Explanation:

3 0
2 years ago
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Justify why a rotten fruit is not truly wasted
ololo11 [35]
Rotten fruit can be consumed by decomposers.
6 0
2 years ago
A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a sp
Levart [38]

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

<u>F₁ = 4 F₀</u>

5 0
3 years ago
A 39.3 g glass thermometer reads 22.0oC before it
ratelena [41]

Answer:

44.85C

Explanation:

Let the specific heat of glass thermometer be 0.84 J/g°C

Let the specific heat of water be 4.186 j/g °C

Let the water density be 1kg/L

136 mL of water = 0.136L of water = 0.136 kg of water = 136 g of water

Since the change of temperature on the glass thermometer is 43.6 - 22 = 21.6 C. We can then calculate the heat energy absorbed to it:

E = m_gc_g \Delta T = 39.3 * 0.84 * 21.6 = 713.06 J

Assume no energy is lost to outside, by the law of energy conservation, this heat energy would come from water

E = m_wc_w(T - T_w) = 713.06

136*4.186(T - 43.6) = 713.06

T - 43.6 = \frac{713.06}{136*4.186} = 1.25

T = 1.25 + 43.6 = 44.85C

6 0
3 years ago
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