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goldfiish [28.3K]
3 years ago
11

Which equation correctly shows how you could calculate [OH-] from [H+]

Chemistry
2 answers:
Pie3 years ago
7 0

Answer:

[OH⁻] = 10⁻¹⁴/[H⁺].

Explanation:

∵ [H⁺][OH⁻] = 10⁻¹⁴.

<em>∴ [OH⁻] = 10⁻¹⁴/[H⁺].</em>

Elenna [48]3 years ago
7 0

Answer:

Kw = [H+][OH-]

Explanation:

For a given solution H+ refers to the hydrogen ion concentration and is indicative of the acidity of the solution. The more the [H+] concentration, higher is the acidity. Similarly, OH- refers to the hydroxide ion concentration and reflects the basicity of the solution. A solution with a higher OH- concentration is said to be basic.

The two are related by considering the dissociation of water:

H2O(l)\rightleftharpoons H+(aq)+ OH-(aq)

The dissociation constant for water, Kw is:

Kw = [H+][OH-]\\\\where\ Kw = 10^{-14} \\\\10^{-14} = [H+][OH-]\\

[H+] = \frac{10^{-14}}{[OH-]}

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Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:
12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = <u>(-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}

∴  mass of S in 2 moles of S: w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g

<em>Given reaction</em>: 2S + 3O₂ → 2 SO₃

<em>In this reaction, the limiting reagent is S</em>

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ <u><em>The amount of heat produced by 42.8 g S:</em></u>

x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ

\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J

(\because 1 kJ = 10^{3} J)

<u>Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

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How much protein one should obtain from diet

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4 gram

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How many mols of chlorine are in 120g of chlorine gas
xz_007 [3.2K]

Answer:

Number of moles of chlorine = 3.38 mol

Explanation:

Given data:

Mass of chlorine = 120 g

Moles of chlorine = ?

Solution:

Formula:

Number of moles = mass/molar mass

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Now we will put the values in formula.

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