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KatRina [158]
3 years ago
5

How to find the energy of an 8 pound weight with e=mc2

Physics
1 answer:
Nastasia [14]3 years ago
7 0
Change the 8 pounds to kilograms (divide it by 2.2). Then multiply the kg by the speed of light (300,000,000 m/sec) squared. You get a very big number. It's the number of joules of energy equivalent to 8 lbs of mass.
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use the drop-down menu to complete the statement. the production of an electric current by a changing magnetic field is known as
Maslowich

The production of an electric current by a changing magnetic field is known as electromagnetic induction.

The phenomenon when the current is produced due to changing magnetic field is given by Faraday.

And this phenomenon is called the electro-magnetic induction or magnetic induction since the electricity is generated due to the fluctuations or variance in the magnetic field.

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3 0
1 year ago
A push or pull is called a force. Unbalanced forces can cause objects to move in many ways but not to move faster. B) move slowe
Allushta [10]

Answer:

but not to

D). float in the air

6 0
3 years ago
A major artery with a 1.7 cm2 cross-sectional area branches into 18 smaller arteries, each with an average cross-sectional area
Alex

Answer:

0.14

Explanation:

Flow rate is the volume flowing through a point at a particular time, in calcuing flow rate we have

Q= v*t

it in terms of Area, we have Q= A*v

Where A= area

v= velocity.

Solving the question , flow rate is constant then

A*v= constant

A(i) v(i)= A(f) v(f)

Where A(i)= initial area= 1.00cm^2

A(f)= final area= 0.400cm^2

V(i) and V(f) are the initial and final velocity respectively and the ratio of the two will gives us the factor

Substitute the values into the equation we have

1 V(i)= 4 V(f)

But we were told that the cross sectional area of 1.00cm^2 branches into 18 smaller arteries.

Then

1 V(i)=0.4 V(f)*(18)

1 V(i)=7.2V(f)

Then if we find the ratio of the velocity, we will get the factor.

V(f)/V(i)= 1/7.2

V(f)/V(i)=0.14

Hence, the factor of the average velocity of the blood reduced when it passes into these branches is 0.14

8 0
3 years ago
A sprinf has a potential energy of 84.08 J and a constant of 342.25 N/m. How far it been stretched? Use potential energy elastic
valina [46]

The spring has been stretched 0.701 m

Explanation:

The elastic potential energy of a spring is the potential energy stored in the spring due to its compression/stretching. It is calculated as

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the elongation of the spring with respect to its equilibrium position

For the spring in this problem, we have:

E = 84.08 J (potential energy)

k = 342.25 N/m (spring constant)

Therefore, its elongation is:

x=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(84.08)}{342.25}}=0.701 m

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8 0
3 years ago
True or False: Any wavelength of light would work for this experiment. Explain your response, including the term quantum or quan
emmainna [20.7K]

Answer:

I think false I don't know if I right but I hoped this help

6 0
3 years ago
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