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1 year ago

What is the limiting reagent when 9.517 g of Fe is allowed to react with 19.34 g of water according to

Chemistry

1 answer:

Drupady [299]1 year ago

6 0

Answer:

4.602 g H20 was used.
14.634 g H20 was left over

Explanation:

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If you place a glass rod over a burning candle, the glass turns

gladu [14]

A. the wax is a both; 1. physical change-solid to liquid.
2. chemical change- burned to CO2 + H20 + heat + carbon as seen as black on the rod
b. the wick is neither; the wick does not change, just provides conduit for wax to flame
c. the glass rod is physical change; the carbon is only deported
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2 years ago

What is the electron arrangement for gallium

Inessa05 [86]

Answer: The electron arrangement for gallium is:

Ar 3d10 4s2 4p1

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2 years ago

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The property of metals to be made into wire is called

ANEK [815]

Metal have some properties like lustrous (shiny), good conductors of electricity and heat,etc. Metals have another property by which metal can be drawn into a wire by hammering on it .This property is called as 'ductility'.

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2 years ago

20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc

bezimeni [28]

Answer:

Concentration of the barium ions = $[Ba^{2+}] = 0.4654 M$

Concentration of the chloride ions = $[Cl^{-}]=0.9308 M$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride = 0.1355 M

$n=0.1355 M\times 0.04389 L=0.005947 mol$

$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

$\frac{1}{2}\times 0.05947 mol=0.029735 mol$ barium hydroxide

Moles of barium hydroxide = 0.029735 mol

$Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)$

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

$=1\times 0.029735 mol= 0.029735 mol$

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL = 63.89 mL = 0.06389 L

Concentration of the barium ions = $[Ba^{2+}]$

$[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M$

$Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

$[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M$

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2 years ago

The amount of energy it takes to remove an electron from an atom is

lara31 [8.8K]

the first ionization energy of an element is the energy needed toremove the outermost, or highest energy, electron from a neutral atom in the gas phase.

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2 years ago