The molarity of the zinc chloride solution will be 0.089 M
<h3>Molarity</h3>
Mole of 7.24 g ZnCl2 = 7.24/136.286 = 0.5312 mol
Total volume of water used in preparing the solution = 300 + 300 = 600 mL
Molarity of the solution = mole/volume = 0.5312/0.6 = 0.089 M
The molarity of the zinc chloride solution is, therefore, 0.089 M
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The hydronium ions increase and the ph goes down.
Answer:
C. +5
Explanation:
Oxygen is always -2. And the sum of the oxidation numbers must be equal to the charge. So:
2x + 7(-2) = -4
2x - 14 = -4
2x = 10
x=5
Answer:
40.34 g
Explanation:
First, we divide the heat to release by the heat of combustion to obtain the required moles of compound:
541.20 kJ/(1160.00 kJ/mol) = 0.4665 mol
So, we have to burn approximately 0.47 mol of the compound. We convert the moles to mass in grams by using the molar mass:
mass = molar mass x moles = 86.47 g/mol x 0.4665 mol = 40.34 g
Therefore, you must burn 40.34 grams of the compound to release 541.20 kJ of heat.
