Earth's _______ prevents most small meteoroids from hitting earth's surface.

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$

$k=\sqrt{\frac{\frac{MR^2}{2}}{M} }$

$k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }$

$k=\sqrt{{\frac{R^2}{2}}$

$k={\frac{R}{\sqrt{2}}$

$k={\frac{1.20m}{\sqrt{2}}$

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = $\frac{2}{3}MR^2$

$k = \sqrt{\frac{\frac{2}{3}MR^2}{M} }$

$k = \sqrt{\frac{2}{3} R^2}$

$k = \sqrt{\frac{2}{3} }*R$

$k = \sqrt{\frac{2}{3}} *1.20$

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of radius

(I) = $\frac{2}{5}MR^2$

$k = \sqrt{\frac{\frac{2}{5}MR^2}{M} }$

$k = \sqrt{\frac{2}{5} R^2}$

$k = \sqrt{\frac{2}{5} }*R$

$k = \sqrt{\frac{2}{5}} *1.20$

k = 0.7560

k ≅ 0.76 m

6 0

4 years ago

If the mass of an object is 200kg and the applied force is 2600N, calculate the Acceleration.

Aliun [14]

Answer:

Explanation:

Mass of object = 200 Kg

Applied force = 2600 N

Acceleration = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m (N = kgm/s²)

a = 2600 kgm/s² / 200 Kg

a = 13 m/s²

6 0

3 years ago

Match the correct sentence together.

Brut [27]

I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B

6 0

2 years ago

Read 2 more answers

Describe the relationship between the direction of the velocity vector and the direction of the acceleration or a body moving in

Law Incorporation [45]

In the centripetal movement, what happens with velocity is that it will remain constant, always pointing in its tangential direction of the trajectory. Said speed, although constant, will have a constant direction that will generate an acceleration that will always point towards the center of the circle radius. Both vectors as the turn is performed will always be perpendicular to each other.

4 0

3 years ago

Hello,

ZanzabumX [31]

the calculated frequency is 932 Hz.

Even for sensors positioned at significant track offsets, the computation method integrates three different speed calculation techniques to produce estimates for arbitrary train speeds. The second technique is comparable, but it combines a running rms with a previously created "dominant frequency method." The third technique calculates train speed using regression analysis and an analytical vibration frequency prediction model.

given-

train is travelling at a constant speed. f=(π v/L)

The actual frequency of the note emitted by the train.

By applying Doppler effect,

n'=n( v + vs/ v-vs )

=200( 340+220 / 340-220 )

=200( 560/120)

=932 Hz

Learn more about frequency here-

brainly.com/question/5102661

#SPJ9

8 0

1 year ago