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Fofino [41]
3 years ago
15

In a solution with a pH of 4, the [OH-] is:1x 10-101x 10-410- 1x 10-8​

Chemistry
1 answer:
e-lub [12.9K]3 years ago
3 0

Answer:

1 x 10^-4

Explanation:

Use the equation pH = -log[OH-}

Rearranging it [OH-] = 10^-pH

Plugging in we get [OH-] = 1 x 10^-4

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The net ionic equation follows:

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