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Mrrafil [7]
3 years ago
15

At the top of the hill, the

Physics
1 answer:
WARRIOR [948]3 years ago
8 0

Answer:

The answer to your question is below

Explanation:

To explain what happens with the ball we must remember the Law of Conservation of Energy.

This law states that the energy can be neither created nor destroyed only converted from one form of energy to another.

Then,

At the top of the hill, the potential energy is maximum and the kinetic energy equals to zero.

When the ball starts to roll down the potential energy will be lower and the kinetic energy will have a low value.

At the middle of the hill, both energies have the same values.

At the end of the hill, the potential energy will be equal to zero and the kinetic energy will be maximum.

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kumpel [21]

Answer:

I'm Pretty sure the answer your looking for is C

4 0
3 years ago
The pitch of a note corresponds to which property of sound wave
Ksivusya [100]
A high pitch sound corresponds to a high-frequency sound wave and a low pitch sound corresponds to a low-frequency sound wave. So, the pitch of a note corresponds to the amount of frequency of a sound wave. Hope this helped!
8 0
3 years ago
How is kinetic energy of an object determined?
pentagon [3]

The formula for kinetic energy is

                     KE = (1/2) (mass) (speed)² .

How you measure the object's mass and speed is up to you.
You'd need different methods for different objects, and in some
cases, you'd need quite a bit of ingenuity.

6 0
4 years ago
A cannon can make a maximum angle of 30 degrees with the horizon. What is the minimum speed of a cannon ball if it must clear a
stiks02 [169]

Answer:

28.3 m/s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Maximum height (H) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

Thus, we can obtain the minimum velocity cannon ball by using the following formula:

H = u²Sine² θ / 2g

10 = u² × (Sine 30)² / 2× 10

10 = u² × (0.5)² / 20

10 = u² × 0.25 / 20

10 = u² × 0.0125

Divide both side by 0.0125

u² = 10/ 0.0125

u² = 800

Take the square root of both side

u = √800

u = 28.3 m/s

Therefore, the minimum speed of the cannon ball is 28.3 m/s

8 0
3 years ago
What is the minimum force required to increase the energy of a car by 68 j over a distance of 12 m? Assume the force is constant
g100num [7]
The wording of this can be bothersome. I think you should be using
E = F * d
E = 68 J
d = 12 m
F = ???

68J = F * 12 m
68J/12 m = F
5.67 N

A <<<<<====== Answer

3 0
3 years ago
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