1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
9966 [12]
3 years ago
13

một ô tô chuyển động nhanh dần đều.Sau 10s vận tốc của xe tăng từ 2m/s lên 6m/s.Tính gia tốc của ô tô

Physics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

áp dụng công thức í, mình thấy câu này có rắc rối gì đâu

You might be interested in
HELP BRAINLIEST!!! I NEED HELP NOW
givi [52]

Answer:

1 kg at 1 m/s

Explanation:

less weight to propell it forward

7 0
3 years ago
Read 2 more answers
Tần số của dao động duy trì
AfilCa [17]
Amman oak smoke skins kaons
8 0
3 years ago
Find what is the ratio of the internal energy of hydrogen UB. To the internal energy of helium UJ for two moles of hydrogen and
finlep [7]

Answer:

Ration of internal energy of hydrogen to the internal energy of helium is equal to \frac{5}{6}

Explanation:

As we know

degree of freedom of hydrogen is 5

Degree of freedom of helium is 3

Internal energy of hydrogen

\frac{5}{2} * 2 * RT = 5 *RT

Internal energy of helium

\frac{3}{2} * 4 * RT = 6 *RT

Ration of internal energy of hydrogen to the internal energy of helium is equal to \frac{5}{6}

4 0
3 years ago
Helphelphelp due in 5 minutes answer the question below
Basile [38]
The correct answer is B
7 0
3 years ago
A body of mass m moves in a horizontal direction such that at time t its position is given byx(t)=at4+bt3+ct,where a, b, and c a
kobusy [5.1K]

Answer:

The acceleration is given by de second derivative of x(t) which is equal to \frac{d^f{2}f(x) }{d^{2}x }=12at^{2} + 6bt m/s^2

Explanation:

a) We have the equation x(t)=at^4+bt^3+ct which is the position of the body of mass m at a time t

Where a, b and c are constants

From the rules of differenciation we have that the first derivative of the position is the velocity  and the second derivative is the acceleration.

Hence the first derivative of the function is equal to 4at^{3} +3bt^{2}+c[/tex] m/s

Don´t forget to write down the unities

Then we have to derivate again this equation, so we have

[tex]\frac{d^{2}f(x) }{d^{2}x }=12at^{2} + 6bt m/s^2[/tex]

b) Remembering the Newton´s laws we know that

F=ma

where:

F is the force

m is the mass

and a is the acceleration

From the first part we know the value of the acceleration which is

\frac{d^{2}f(x) }{d^{2}x }=12at^{2} + 6bt m/s^2

So using the second law formula and replacing the values we have that

F=m(\frac{d^{2}f(x) }{d^{2}x }=12at^{2} + 6bt ) N

Remember the that N= Newton which is kg*m/s^2

4 0
3 years ago
Other questions:
  • Which of the following describes the difference between the classes of levers?
    10·1 answer
  • 1. It is dangerous "cutting" in front of trucks when turning left or passi g them and then slowing down
    8·1 answer
  • An astronaut, whose mission is to go where no one has gone before, lands on a spherical planet in a distant galaxy.
    8·1 answer
  • When operated on a household 110.0 V line, typical hair dryers draw about 1450 W of power. The current can be modeled as a long,
    7·1 answer
  • Can someone explain to me what Murphy's law is and how it works?
    6·1 answer
  • A circuit is built based on this circuit diagram. What is the equivalent resistance of the circuit?
    9·2 answers
  • A proton is placed in a uniform electric field and then released. Then an electron is placed at this same point and released. Wh
    14·1 answer
  • A thin, uniform metal bar, 2.00 m long and weighing 90.0 N, is hanging vertically from the ceiling by a frictionless pivot. Sudd
    5·1 answer
  • an object on a planet has a mass of 243 Kg. what is the acceleration of the object, if the radius of the planet is 2.32 x 10^7m
    15·1 answer
  • which one of these represent total momentum of a system of two particles traveling one against the other?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!